필터 지우기
필터 지우기

how to sort histogram generated count and corresponding gray value.. pls help

조회 수: 6 (최근 30일)
m=imread('ll.bmp');
[count,gray]=imhist(m);
the answer is:
i want to sort the count and corresponding gray value..
and delete the zero count values answer like this..

채택된 답변

ARJUN K P
ARJUN K P 2015년 5월 20일
편집: ARJUN K P 2015년 5월 20일
i got answer from :
https://www.facebook.com/thematrixcoded
the code is :
m=imread('ll.bmp');
>> [c,g]=imhist(m);
>> K=[c,g];
>> Ks=sortrows(K);
Ki=Ks(end:-1:1,:);
Ki(Ki(:,1)==0,:)=[];
>> Ki
Thanku all for supporting
  댓글 수: 1
Image Analyst
Image Analyst 2015년 5월 20일
It does the same thing that I did but combined the counts and gray level arrays into a single 2D array (which we didn't know you wanted to do).

댓글을 달려면 로그인하십시오.

추가 답변 (2개)

Image Analyst
Image Analyst 2015년 5월 18일
Don't use gray as a variable name - it's the name of a built in function that creates a colormap, and you just blew it away.
I don't know why you need to, but to get rid of array elements with zero counts
[count, grayLevels]=imhist(m);
rowsToDelete = count == 0;
count(rowsToDelete) = [];
grayLevels(rowsToDelete) = [];
  댓글 수: 5
Image Analyst
Image Analyst 2015년 5월 18일
To sort in reverse order, simply use fliplr()
count = fliplr(count)
grayLevels = fliplr(grayLevels);
Image Analyst
Image Analyst 2015년 5월 19일
% Sort count in descending order.
[sortedCounts, sortIndexes] = sort(count, 'descend');
% Sort grayLevels the same way.
grayLevels = grayLevels(sortIndexes);

댓글을 달려면 로그인하십시오.


ARJUN K P
ARJUN K P 2015년 5월 19일
sir you mistaken, i want sort the count in decreasing order...
eg:
before sorting
after sorting
i want ans like
  댓글 수: 2
ARJUN K P
ARJUN K P 2015년 5월 19일
its not i want.. i want to sort the count in decreasing order and corresponding gray value.. that i show in above figure...

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Shifting and Sorting Matrices에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by