How to write to screen a set of variables with mixed types?

hello,

I am trying to write to screen a set of variables with mixed types. I have the code below

and I get the following display:

d=0.7874 mm , epsr=2.1 >>

a='d=0.7874 mm , epsr=2.1';
m=3;
k=7;
u=7.853535;
fprintf('%s %i \t %10.5f \n',[a m u])

d=0.7874 mm , epsr=2.1□□ 

help would be appreciated.

Thank you

[Stephen23]

a='d=0.7874 mm , epsr=2.1';
m=3;
u=7.853535;
fprintf('%s %i \t %10.5f \n',a,m,u)

d=0.7874 mm , epsr=2.1 3 	    7.85353 

Answer 1

[Manikanta Aditya]

HI @Robert Jones

It looks like you're trying to print a string along with integer and floating-point variables using fprintf. The issue arises because you're trying to concatenate different types into a single array, which fprintf doesn't handle well. Instead, you should pass each variable separately to fprintf.

Here's how you can modify your code to correctly display the variables:

a = 'd=0.7874 mm , epsr=2.1';
m = 3;
k = 7;
u = 7.853535;

% Use fprintf with separate arguments for each variable
fprintf('%s %i \t %10.5f \n', a, m, u);

d=0.7874 mm , epsr=2.1 3 	    7.85353 

This will correctly print the string a, the integer m, and the floating-point number u in the desired format.

If you want to include the variable k as well, you can add it to the fprintf statement:

fprintf('%s %i \t %i \t %10.5f \n', a, m, k, u);

d=0.7874 mm , epsr=2.1 3 	 7 	    7.85353 

This way, each variable is passed as a separate argument to fprintf, ensuring they are printed correctly.

Refer to the following doc:

• https://www.mathworks.com/help/releases/R2023a/matlab/ref/fprintf.html

I hope this helps.

[Robert Jones]

Belated Thank you

Answer 2

[Walter Roberson]

a='d=0.7874 mm , epsr=2.1';
m=3;
u=7.853535;
temp = [a m u]

temp = 'd=0.7874 mm , epsr=2.1□□'

length(a)

ans = 22

length(temp)

ans = 24

temp(end-1:end), temp(end-1:end)+0

ans = '□□'

ans = 1×2

3 7

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You are using [] to concatenate a character vector and numeric items. As described in https://www.mathworks.com/help/matlab/matlab_prog/valid-combinations-of-unlike-classes.html the result of concatenating a character vector and numeric items is a character vector, with each of the numeric items having first been converted to uint16() after fractions are dropped. The numeric values are not first converted to printable representations: they are treated as code-points.

So you start with your vector of length 22, and concatenate on two code points, giving a result that is a vector of length 24, the last two code points of which are 3 and 7.

Your error was in concatenating the values first, instead of using individual parameters to fprintf()