Warning: Results may be inaccurate because of an ill-conditioned Jacobian whose reciprocal condition number is 3.23252e-20.

조회 수: 3 (최근 30일)
Hey!
I was trying to solve these equations and was getting an error as : Warning: Results may be inaccurate because of an ill-conditioned Jacobian whose reciprocal condition number is 3.23252e-20. > In bvp4c (line 288) in compressiblechannel (line 15). How should I resolve it. here's my code and equations.
Thanks for your help in advance.
code:
close all
clear all
G = -1;
%Na = 0.86;
gamma = 1.4;
Pr = 0.71;
M = 0.1;
xstart = -1;
xend = 1;
nx = 51;
x = linspace(xstart,xend,nx);
solinit = bvpinit(x, [0;0;1;0]);
sol = bvp4c(@(y,z)bvpfcn(y,z,G, Pr, M, gamma), @bcfcn, solinit);
Warning: Results may be inaccurate because of an ill-conditioned Jacobian whose reciprocal condition number is 3.23252e-20.
% Extract variables from solution
U = sol.y(1,:); % U from solution
dUdy = sol.y(2,:); % dU/dy from solution
T0 = sol.y(3,:); % T0 from solution
dT0dy = sol.y(4,:); % dT0/dy from solution
y = sol.x; % y values (independent variable)
%Calculate d^2U/dy^2 using the equation from bvpfcn
% d2Udy2 = (dUdy .* dT0dy) + G * exp(T0);
% Plot d^2U/dy^2 vs y
figure(3)
% plot(d2Udy2, y);
% hold on
plot(diff(dUdy), y(2:end));
xlabel('d^2U/dy^2');
ylabel('y');
title('Plot of d^2U/dy^2 vs y');
figure(1)
plot(sol.y(1,:), sol.x)
xlabel ('U')
ylabel ('y')
figure(2)
plot(sol.y(3,:), sol.x)
xlabel ('T0')
ylabel ('y')
function dzdy = bvpfcn(y,z,G,Pr,M,gamma )
U = z(1);
dUdy = z(2);
T0 = z(3);
dT0dy = z(4);
dzdy = zeros(4,1);
dzdy(1) = dUdy;
dzdy(2) = -dUdy*dT0dy*0.76*(T0^ -1) + G/(T0^0.76);
dzdy(3) = dT0dy;
dzdy(4) = -Pr*M^2*(gamma-1)*((T0^0.76)*(dUdy^2));
end
function res = bcfcn(za,zb)
res = [za(1);zb(1);za(3);zb(3)-1];
end
equation:
where mu0 = T0^ 0.76 and boundary conditions are: U = 0 at y= +1 and y = -1 and T0 = 0 at y =-1 and T0 = 1 at y = +1
  댓글 수: 1
Torsten
Torsten 2024년 11월 11일
편집: Torsten 2024년 11월 11일
It seems mu0 = exp(-T0) was a better choice than mu0 = T0^0.76 for "bvp4c".
Since you divide by T0^0.76, T0 mustn't become zero anywhere. But you set T0 = 0 at y = -1. This might be a problem although it's only in a boundary point.
Another problem is that T0 should not become negative in the course of the iterations because T0^0.76 would produce a complex number.

댓글을 달려면 로그인하십시오.

답변 (0개)

카테고리

Help CenterFile Exchange에서 Numerical Integration and Differential Equations에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by