Adding a column to a UITable and then using it.

After a few hours of trying I finally was able to add a column to a UITable
A = zeros([1 size(app.StimInputTable.Data,1)]);
app.StimInputTable.Data.Var4 = A'; % Have to make A a column vector!
for ii = 1:size(app.StimInputTable.Data,1)
app.StimInputTable.Var4(ii) = ...
app.StimInputTable.Data.Var3(ii)/app.StimInputTable.Data.Var2(ii);
But now...
assigning a value to Our new column Var4 gives me
Unrecognized method, property, or field 'Var4' for class 'matlab.ui.control.Table'.
It know what app.StimInputTable.Data.Var3(ii)/app.StimInputTable.Data.Var2(ii);
is so now put it in Var4! How hard can that be?
K>> app.StimInputTable.Data
ans =
4×4 table
Var1 Var2 Var3 Var4
____ ____ ____ ____
4 5 0 0
5 4 1 0
2 3 2 0
3 2 5 0
I can do it 1 row at a time from theCommand window:
K>> app.StimInputTable.Data
ii = 1 (etc)
K>> app.StimInputTable.Data.Var4(ii) = app.StimInputTable.Data.Var3(ii)/app.StimInputTable.Data.Var2(ii)
Although the "answer" I get is my whole
app =
MouseOdor4 with properties:
MouseOdor: [1×1 Figure]
all the properties of the whole app I won't bore you with
K>> app.StimInputTable.Data
ans =
4×4 table
Var1 Var2 Var3 Var4
____ ____ ____ _______
4 5 0 1
5 4 1 2
2 3 2 0.66667
3 2 5 2.5
Look it worked!
Next step if you don't mind anwering is to sort the table by the Var4 column

댓글 수: 1

BTW I tried addvars() for a while as help said to do but never got that to work following all the examples the best I could

댓글을 달려면 로그인하십시오.

 채택된 답변

Voss
Voss 2024년 7월 21일
편집: Voss 2024년 7월 21일

0 개 추천

app.StimInputTable.Data.Var4 = app.StimInputTable.Data.Var3./app.StimInputTable.Data.Var2;
%                 ^^^^^ you were missing the .Data

댓글 수: 4

Thanks I saw that after I pasted the code here. I fixed that and now it runs through that callback and then quits running in the App Designer debugger with NO errors either in the command window nor in App Designer.
My program continues to run OK but I can no longer debug.
Voss
Voss 2024년 7월 22일
So no breakpoints are being triggered?
Added some string stuff which completes but now when I exit the callback it halts here so maybe that is a clue?
methods (Access = protected, Sealed = true)
function newCallback = createCallbackFcn(app, callback, requiresEventData)
if nargin == 2
requiresEventData = false;
end
ams = appdesigner.internal.service.AppManagementService.instance();
newCallback = @(source, event)executeCallback(ams, ...
app, callback, requiresEventData, event);
end
Is there some magic I have to do at the end of a callback function?
Voss
Voss 2024년 7월 22일
No magic required. What is the problem you are describing?

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 App Building에 대해 자세히 알아보기

제품

릴리스

R2023b

질문:

2024년 7월 21일

댓글:

2024년 7월 22일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by