Dynamic matrix columns combinations

조회 수: 4 (최근 30일)
mrish
mrish 2024년 6월 11일
댓글: Stephen23 2024년 6월 11일
Hello,
I would like to find all possible combinations of a matrix columns, with each column contribute a value, in each itteration of a loop. The matrix size changes in each itteration. For example:
A = [1 2 3
4 5 6
7 8 9].
should produce:
1 2 3
1 2 6
1 5 3 etc.
but should not produce:
1 4 2 for example.
My problems:
  • When insert the matrix to combvec function nothing happens. The function accept vectors - and since I do it with different matrix size in each Itteration of a loop I can't write it manually.
  • ndgrid also requires vectors - and since I need to choose a combination index in other variable - I'm not clear how this happens.
  • I don't have combination function in my Matlab version.
Is there a way to define vectors dynamically in a loop? any idea on to how overcome this? Do I need to write a combination function myself?
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Stephen23
Stephen23 2024년 6월 11일
"Is there a way to define vectors dynamically in a loop?"
What exactly do you mean?

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답변 (1개)

Stephen23
Stephen23 2024년 6월 11일
편집: Stephen23 2024년 6월 11일
"any idea on to how overcome this? Do I need to write a combination function myself?"
Use NDGRID with some comma-separated lists:
A = [1,2,3;4,5,6;7,8,9]
A = 3x3
1 2 3 4 5 6 7 8 9
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C = num2cell(A,1);
N = numel(C);
[C{:}] = ndgrid(C{:});
M = reshape(cat(1+N,C{:}),[],N)
M = 27x3
1 2 3 4 2 3 7 2 3 1 5 3 4 5 3 7 5 3 1 8 3 4 8 3 7 8 3 1 2 6
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  댓글 수: 1
Stephen23
Stephen23 2024년 6월 11일
If you really need just one combination on each loop iteration, then use the methods already described e.g.:
Note that for large arrays you will have a very large number of combinations.

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