Solving a linear programming problem uising linprog

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Sergio
Sergio 2024년 5월 23일
댓글: Rena Berman 2024년 7월 10일
I have the given linear program to solve.
To solve this I prepare the following for the constraints on each of the six variables:
A = [110 205 160 160 420 260;
4 32 13 8 4 14;
2 12 54 285 22 80];
b = [2000 55 800];
where the function to be minimized with constraints:
f = [3 24 13 9 20 19];
lb = [0,0,0,0,0,0];
ub = [4,3,2,8,2,2];
Is solved by:
options = optimoptions('linprog','Algorithm','dual-simplex');
[x,fval,exitflag,output] = linprog(f,A,b,lb,ub,options)
.
I get "Error using linprog (line 182)
LINPROG requires the following inputs to be of data type double: 'LB'"
How do I prepare the linear inequalities correctly?
With Thanks
  댓글 수: 4
Sergio
Sergio 2024년 7월 7일
@Torsten I acidentally edited an old question with a new question, I tried to delete it , but that didn't work!
Rena Berman
Rena Berman 2024년 7월 10일

(Answers Dev) Restored edit

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채택된 답변

Torsten
Torsten 2024년 5월 23일
편집: Torsten 2024년 5월 23일
A = -[110 205 160 160 420 260;...
4 32 13 8 4 14;...
2 12 54 285 22 80];
b = -[2000; 55; 800];
Aeq = [];
beq = [];
where the function to be minimized with constraints:
f = [3 24 13 9 20 19];
lb = [0,0,0,0,0,0];
ub = [4,3,2,8,2,2];
Is solved by:
options = optimoptions('linprog','Algorithm','dual-simplex');
[x,fval,exitflag,output] = linprog(f,A,b,Aeq,beq,lb,ub,options)
Optimal solution found.
x = 6x1
4.0000 0 0 4.5000 2.0000 0
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fval = 92.5000
exitflag = 1
output = struct with fields:
iterations: 3 algorithm: 'dual-simplex-highs' constrviolation: 0 message: 'Optimal solution found.' firstorderopt: 1.7764e-15

추가 답변 (1개)

Ayush Modi
Ayush Modi 2024년 5월 23일
편집: Ayush Modi 2024년 5월 23일
Hi Sergio,
The error you are getting is because of extra parameters in the function call. Here is how you can make the call to the "linprog" function with lower and upper bounds:
x = linprog(f,A,b,Aeq,beq,lb,ub,options) % Maximum 8 parameters
Refer to the following MathWorks documentation for more information on syntax of "linprog" function:

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