I have a code in python and want to convert it in matlab format
이전 댓글 표시
def DEM(Km, Gm, Ki, Gi, alphai, phii, phi0=0.0, r=1000, phitol=1.0E-10, gamma=0.01):
phi = np.sum(phii)
fraci = phii / np.sum(phi)
ci = fraci * alphai / r
n = int(np.ceil((np.log(1.0 - phi) - np.log(1.0 - phi0)) / np.sum(np.log(1.0 - ci))))
m = len(alphai)
def func(r):
f = np.empty(m)
f[0] = np.log(alphai[0] / r[0]) + np.log(1.0 - phi0 / phi) - np.log(
1 - ((1.0 - phi) / (1.0 - phi0)) ** (1.0 / n))
for j in range(1, m):
f[j] = f[j - 1] + np.log(alphai[j] / r[j]) + np.log(r[j - 1] / alphai[j - 1] - fraci[j - 1])
return f
def fprime(r):
jac = np.diag(-1.0 / r)
for j in range(0, m - 1):
jac[j + 1:, j] = -1.0 / r[j] + 1.0 / (r[j] - fraci[j] * alphai[j])
return jac
r0 = r * np.ones(m)
ri = fsolve(func, r0, fprime=fprime, factor=0.1)
ci = fraci * alphai / ri
thetai = theta(alphai)
fi = f(alphai, thetai)
K = np.empty(n)
G = np.empty(n)
phi = np.empty(n)
K_ = Km
G_ = Gm
phi_ = phi0
for i in range(n):
dphi = ci[0] * (1.0 - phi_)
K_, G_ = KG(K_, G_, Ki[0], Gi[0], ci[0], thetai[0], fi[0])
phi_ += dphi
for j in range(1, m):
dphi *= ci[j] * (1.0 - ci[j - 1]) / ci[j - 1]
K_, G_ = KG(K_, G_, Ki[j], Gi[j], ci[j], thetai[j], fi[j])
phi_ += dphi
K[i] = K_
G[i] = G_
phi[i] = phi_
return K, G, phi
답변 (1개)
Steven Lord
2024년 4월 15일
0 개 추천
Do you need to convert the code or would being able to run the code in MATLAB be sufficient? If the latter, see the documentation for instructions on how to run Python code in MATLAB.
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