Why is my error not exactly 0
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I wrote a very simple upwind difference scheme for the equation with , but for some reason the error is not exactly 0.
%u_t+u_x=0
space=[0.01,0.005,0.0025,0.00125];
error=zeros(size(space));
for j=1:size(space,2)
dx=space(j);
dt=dx;
u=sin(0:dx:1);
n=size(u,2);
T=1/dt;
for i=1:1
ul=[sin(-dx-dt*(i-1)),u(1:(n-1))];
u=(1-dt/dx)*u+ul*dt/dx;
end
error(j)=norm(u-sin((0:dx:1)-dt),1)/n;
end
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답변 (1개)
Image Analyst
2024년 4월 13일
error is a built-in function. You must not use it as a name for your variable.
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