Matlab code calculation error

조회 수: 1 (최근 30일)
Jacob
Jacob 2024년 4월 8일
댓글: Jacob 2024년 4월 10일
Hello,
I am trying to calculate the width of a bandpass filter with matlab code but I am coming up with the wrong calculation and I am not sure what I need to change in my matlab code to get the right calculation.
This is the code I am using below
L = 51;
wc=0.2*pi;
Beta=1;
nn=0:(L-1); % filter length
hh=Beta*cos(wc*nn); % filter impulse response , 2/L+1
ww=0:(pi/500):(0.5*pi);
HH=freqz(hh,1,ww);
max_mag = max(abs(HH));
Beta = 1/max_mag;
hh=Beta*cos(wc*nn);
HH=freqz(hh,1,ww);
Half_max_mag = abs(HH)/sqrt(2);
xlabel('Normalized radian frequency')
jkl=find(abs(HH)>=Half_max_mag);
w2 = max(ww(jkl))
w1 = min(ww(jkl))
bandwidth = w2-w1
figure(2)
subplot(2,1,1);
plot(ww/pi,abs(HH))
yline(max(abs(HH))/sqrt(2), '--g', '3db points')
xline(w1/pi, '--r', 'w1');
xline(w2/pi, '--b', 'w2');
subplot(2,1,2);
plot(ww/pi,angle(HH))
These are the Values I am getting with this code below.
W1 = 0
W2 = 1.5708
bandwidth = 1.5708
These are the Values I am supposed to be getting with this code below but I am not getting them and I can't figure out what code to change to get that happen.
W1 = 0.5777
W2 = 0.6842
bandwidth = 0.1065

채택된 답변

AH
AH 2024년 4월 9일
Change this line Half_max_mag = abs(HH)/sqrt(2); to Half_max_mag = max(abs(HH))/sqrt(2);
  댓글 수: 1
Jacob
Jacob 2024년 4월 10일
That worked Thank you!

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Subplots에 대해 자세히 알아보기

태그

제품


릴리스

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by