How can I fix "Index in position 2 exceeds array bounds" in for loop?

조회 수: 1 (최근 30일)
Mikhail
Mikhail 2024년 4월 3일
댓글: Mikhail 2024년 4월 6일
p=1;c=[1 0 4 8];n=4;b=[];j=1;
b=a(1,1)
a=flip(c)
for i=n-1:-1:1
b(1,i)=b(1,i+1)*p+a(1,i);
end
b

채택된 답변

Mathieu NOE
Mathieu NOE 2024년 4월 3일
hello
to make your code work, b should be initiallized with same dimensions as a (as a vector, not just one scalar)
also it's not clear when you write b=a(1,1) if you meant the first or last element (iteration) of vector b
p=1;
c=[1 0 4 8];
n=4;
j=1;
a=flip(c);
b=zeros(size(a));
b(1,4)=a(1,1);
for i=n-1:-1:1
b(1,i)=b(1,i+1)*p+a(1,i);
end
b
b = 1x4
20 12 8 8
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추가 답변 (1개)

Torsten
Torsten 2024년 4월 3일
편집: Torsten 2024년 4월 3일
When you set
b = a(1,1)
, a is undefined in your code from above.
Further, b is a scalar value, namely b = a(1,1). When you enter the for-loop, you want to compute b(1,3) as
b(1,3) = b(1,4)*p+a(1,3)
. But b(1,4) does not exist.
Maybe you want to set
b(1,4) = a(1,1)
instead of
b = a(1,1)
- I don't know.

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