Interpolate x,y coordinates and timesteps
이전 댓글 표시
Heallo,
I have an array M with x, y, coordinates points in the 1st and 2nd column [x= M(2:end,1); y= M(2:end,2)]. The following columns are the values (for example temperatures) for different timesteps [timesteps = M(1,3:end].
How can I interpolate the x,y coordinates and the timesteps?
clc
clear
M(5,7)=0;
M(1,2:7)=0:10:50;
M(2:5,1)=1:4;
M(2:5,2)=1:0.5:2.5;
M(2,3:7)=100:3:112;
M(3,3:7)=110:3:122;
M(4,3:7)=120:3:132;
M(5,3:7)=120:3:132;
댓글 수: 5
Mathieu NOE
2024년 3월 4일
seems to me (if I understand correctly) that x and y are not independant variables.
we can do a 2D interpolation beetween x and time (or y and time , as x and y are linked) , but we cannot make any 3D interpolation as if x,y and time are independant data.

Patrick Frey
2024년 3월 4일
Mathieu NOE
2024년 3월 5일
exact !!
Patrick Frey
2024년 3월 5일
Mathieu NOE
2024년 3월 5일
my pleasure !!
답변 (1개)
In your example, you only have a 2D M array, but I guess what you want is a 3D interpolation, so with another dimension in M ?
M = [[103,113,123,123]',[106,116,126,126]',[109,119,129,126]',[112,122,132,132]'];
% Building an example of a 3 dimensional array
values(:,1,:) = M;
values(:,2,:) = M*1.05;
values(:,3,:) = M*1.1;
values(:,4,:) = M*1.15;
timesteps = (20:10:50)';
x = (1:4)';
y = (1:0.5:2.5)';
% query values
x_query = [1.1 3.2];
y_query = [1.3 2.2];
time_query = [21 45];
query_values = interp3(x,y,timesteps,values,x_query,y_query,time_query)
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