How I can to resolve the code below?

조회 수: 2 (최근 30일)
Ky
Ky 2024년 1월 24일
답변: Sandeep Mishra 2024년 9월 18일
function [x, y, z] = Forward_Kinematics1(theta1, theta2, theta3)
syms x y z
% kinematic parameters
R = 94.52;
L1 = 170;
L2 = 319.5;
r = 65;
% Calculate sine and cosine values
c1 = cosd(theta1); s1 = sind(theta1);
c2 = cosd(theta2); s2 = sind(theta2);
c3 = cosd(theta3); s3 = sind(theta3);
% define B1'
B1 = [0; -R - L1*c1 + r; L1*s1];
% define B2'
B2 = [(-sqrt(3)/2)*(-R-L1*c2+r); (-1/2)*(-R-L1*c2+r); L1*s2];
% define B3'
B3 = [(sqrt(3)/2)*(-R-L1*c3+r); (-1/2)*(-R-L1*c3+r); L1*s3];
% Define constants
a1 = 2*(B1(1) - B2(1)); a2 = 2*(B1(1) - B3(1));
b1 = 2*(B1(2) - B2(2)); b2 = 2*(B1(2) - B3(2));
c1 = 2*(B1(3) - B2(3)); c2 = 2*(B1(3) - B3(3));
d1 = (B2(1)^2 + B2(2)^2 + B2(3)^2) - (B1(1)^2 + B1(2)^2 + B1(3)^2);
d2 = (B3(1)^2 + B3(2)^2 + B3(3)^2) - (B1(1)^2 + B1(2)^2 + B1(3)^2);
% Define coefficients for z
A = 1;
B = -2*B1(3);
C = B1(3)^2 - L2^2 + (B1(1))^2 + (B1(2))^2;
% Define equations as symbolic expressions
eq1 = a1 * x + b1 * y + c1 * z - d1;
eq2 = a2 * x + b2 * y + c2 * z + d2;
eq3 = A * z^2 + B * z + C;
  댓글 수: 2
Anjaneyulu Bairi
Anjaneyulu Bairi 2024년 1월 24일
can you post the error that you are getting?
Thanks
Ky
Ky 2024년 1월 24일
I'm calculating Forward kinematics for delta robot. Programe of me is bellow:
function [x, y, z] = Forward_Kinematics1(theta1, theta2, theta3)
syms x y z real
% kinematic parameters
R = 94.52;
L1 = 170;
L2 = 319.5;
r = 65;
% Calculate sine and cosine values
c1 = cosd(theta1); s1 = sind(theta1);
c2 = cosd(theta2); s2 = sind(theta2);
c3 = cosd(theta3); s3 = sind(theta3);
% define B1'
B1 = [0; -R - L1*c1 + r; L1*s1];
% define B2'
B2 = [(-sqrt(3)/2)*(-R-L1*c2+r); (-1/2)*(-R-L1*c2+r); L1*s2];
% define B3'
B3 = [(sqrt(3)/2)*(-R-L1*c3+r); (-1/2)*(-R-L1*c3+r); L1*s3];
% Define constants
a1 = 2*(B1(1) - B2(1)); a2 = 2*(B1(1) - B3(1));
b1 = 2*(B1(2) - B2(2)); b2 = 2*(B1(2) - B3(2));
c1 = 2*(B1(3) - B2(3)); c2 = 2*(B1(3) - B3(3));
d1 = (B2(1)^2 + B2(2)^2 + B2(3)^2) - (B1(1)^2 + B1(2)^2 + B1(3)^2);
d2 = (B3(1)^2 + B3(2)^2 + B3(3)^2) - (B1(1)^2 + B1(2)^2 + B1(3)^2);
% Define coefficients for z
A = 1;
B = -2*B1(3);
C = B1(3)^2 - L2^2 + (B1(1))^2 + (B1(2))^2;
% Define equations as symbolic expressions
eq1 = a1 * x + b1 * y + c1 * z - d1;
eq2 = a2 * x + b2 * y + c2 * z + d2;
eq3 = A * z^2 + B * z + C;
% Convert equations to functions
equations = matlabFunction([eq1; eq2; eq3], 'vars', [x; y; z]);
% Solve the system of equations
initial_guess = [0; 0; 0];
result = fsolve(equations, initial_guess);
% Extract results
x = result(1);
y = result(2);
z = result(3);
% Display results
fprintf('Nghiệm x: %.4f\n', x);
fprintf('Nghiệm y: %.4f\n', y);
fprintf('Nghiệm z: %.4f\n', z);
end
and error, when I run program is
[x, y, z] = Forward_Kinematics1(0,0,0)
Not enough input arguments.
Error in symengine>@(x,y,z)[x.*(-3.455787771261424e+2)-y.*5.9856e+2;x.*3.455787771261424e+2-y.*5.9856e+2;z.^2-6.227201960000001e+4]
Error in fsolve (line 264)
fuser = feval(funfcn{3},x,varargin{:});
Error in Forward_Kinematics1 (line 46)
result = fsolve(equations, initial_guess);
Caused by:
Failure in initial objective function evaluation. FSOLVE cannot continue.

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답변 (1개)

Sandeep Mishra
Sandeep Mishra 2024년 9월 18일
Hi Ky,
I executed the code snippet in MATLAB R2022a and encountered the same error.
After investigating further, I came across a relevant MATLAB Answers post addressing a similar issue:
The root cause of the error is related to the fsolvefunction, to resolve this, you can update the code snippet by passing the inputs in the following manner:
equations = matlabFunction([eq1; eq2; eq3], 'Vars', {[x; y; z]});
Please refer to the below MathWorks documentation to learn more about ‘fsolvefunction of MATLAB:
I hope this helps.

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