Populate a vector to a specified threshold limit

조회 수: 2 (최근 30일)
Matt
Matt 2011년 11월 9일
Hi; I'm trying to generate an array by calculating 'y from a large list of random numbers 'x', but I want the vector to stop populating once it reaches 5000 entries.
Here's the code to generate the vector (and reject all values less than -5 and greater than 25)
a=10; T=3;
x = rand(10000,1);
y=a+((T/2).*(tan(pi.*(x-(0.5)))));
y(y<-5)=[];
y(y>25)=[];
So this generates entries in the vector 'y', but I want the vector to stop populating after it reaches 5000 entries. I've tried using a while loop and playing around with counting the entries in the array then trying to break out of the loop, but I can't seem to get it to work. Any help is appreciated! Thanks!

채택된 답변

Fangjun Jiang
Fangjun Jiang 2011년 11월 9일
Can you generate a reasonably large random number, e.g. x=rand(50000,1), then after y(y<-5)=[] and y(y>25)=[] operation, it is almost certain that y is more than 5000 in length? Then you can do y(5001:end)=[].
It is certainly possible to do it using a while-loop, but probably won't be fast.
a=10; T=3;
y=zeros(5000,1);
k=1;
while k<=5000
x= rand;
temp=a+((T/2).*(tan(pi.*(x-(0.5)))));
if -5<=temp && temp<=25
y(k)=temp;
k=k+1;
end
end
  댓글 수: 1
Matt
Matt 2011년 11월 9일
Hah, you know the expression 'can't see the forest for the trees'....
Funny that I didn't think of just deleting the leftovers at the end of a large vector. That works perfectly and yes if you use enough values, you keep the random nature of the problem.
Thanks!
PS: you're right about the speed of the while-loop taking a very long time

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by