Create 30 minute bins by reading time stamps
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I have a file with time stamps, due to error in the files (gaps in time due to faulty equipment) binning 30 minute sections using the following code creates errors in the actograms produced.
function[Average] = Av_30min(y)
Average = zeros(288,size(y,2));
k = 1;
for l =1:288
Average(l,1) = mean(y(k:k+(round(length(y)/288)-1),1));
k = k+((round(length(y)/288)-1));
end
end
I want to read from say 11:30:00 - 12:00:00 and average this bin and so on and so forth. Can anyone help?
Thanks
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채택된 답변
Star Strider
2023년 12월 14일
What do the ‘Calculated time’ values represent? Are they fractions of a day (from about ¼ to about 3¼ days) or something else?
Until that is resolved, converting them into something useful is not likely to be possible.
% imshow(imread('Timestamps in output.PNG'))
% function readfaultydata
% clear; close all
Data = xlsread('Data.xlsx',1,'A2:F60099');
T1 = readtable('Data.xlsx', 'VariableNamingRule','preserve');
t = Data(:,1);
dt = t(2)-t(1); % Your sample rate
t = (1:length(t))*dt; % Linear timeline
x = Data(:,3);
y = Data(:,4);
z = Data(:,5);
subplot(311);plot(t,x);grid;
subplot(312);plot(t,y);grid;
subplot(313);plot(t,z);grid;
T1 = sortrows(T1,1);
T1 = fillmissing(T1, 'nearest') % Sorted With NaN Values Interpolated
VN = T1.Properties.VariableNames;
% timestats = [mean(diff(T1{:,1})) std(diff(T1{:,1}))]
Ts = mean(diff(T1{:,1}))
Fs = 1/Ts
Fn = Fs/2;
[XYZr, tr] = resample(T1{:,[3 4 5]}, T1{:,1}, Fs);
% format longg
% XYZr(end-4:end,:)
XYZr = XYZr(1:end-3,:);
tr = tr(1:end-3);
% XYZr(end-4:end,:)
x = XYZr(:,1);
y = XYZr(:,3);
z = XYZr(:,3);
figure
plot(tr, XYZr)
grid
xlabel([string(VN{1}) + " (Sorted & Resampled)"])
ylabel("Amplitude")
figure
tiledlayout(3,1)
for k = 1:size(XYZr,2)
nexttile
plot(tr, XYZr(:,k))
grid
ylabel("Amplitude")
title(["Column "+k])
end
xlabel([string(VN{1}) + " (Sorted & Resampled)"])
figure
scatter3(x,y,z, 10, z, '.')
colormap(turbo)
grid on
xlabel('X')
ylabel('Y')
zlabel('Z')
.
댓글 수: 7
Star Strider
2023년 12월 18일
My pleasure!
If my Answer helped you solve your problem, please Accept it!
.
추가 답변 (2개)
Alexander
2023년 12월 13일
Whers is this file Data.xlsx from? I think someone has corrupted the "Calculated time" column. In this column is a mixture of formulars and manual input (see cell A1793:A1795, e.g.). If you copy A3 and paste it to A60099 your timeline is correct your program might run (I'll attach a modified xlsx). Hopefully this was your intension.
댓글 수: 2
Alexander
2023년 12월 14일
Here some code, w/o editing the xlsx:
function readfaultydata
clear; close all
Data = xlsread('Data.xlsx',1,'A2:F60099');
t = Data(:,1);
dt = t(2)-t(1); % Your sample rate
t = (1:length(t))*dt; % Linear timeline
x = Data(:,3);
y = Data(:,4);
z = Data(:,5);
subplot(311);plot(t,x);grid;
subplot(312);plot(t,y);grid;
subplot(313);plot(t,z);grid;
end
Hope it helps.
Mathieu NOE
2023년 12월 13일
hello
this is certainly not the best and most modern way to solve your problem , but as I have not really started digging with timetables and alike , so here's a (very) low level approach
someone younger / smarter may come up with a 2 lines solutions, but for the time being this is what I can offer
in very short , I am simply looking where 30 or 00 min appears in your data and the duration is exactly 180 samples (= 30 mins) then this data is averaged and saved
the new time data correspond to the beginning of the 30 min buffer
also I didn't copy paste the header line, I think you could manage that by yourself...
result should look like :
code
y = xlsread('Data.xlsx');
%% convert y firt column (time HH:MM:SS) to hours (h), minutes (m) and seconds (s)
h = y(:,1)*24;
m = 60*(h - floor(h));
s = 60*(m - floor(m));
h = floor(h);
m = floor(m);
s = round(s);
id1 = (m ==30); % find time index matching the 30 min timestamp
[begin1,ends1] = find_start_end_group(id1);
id2 = (m ==00); % find time index matching the 00 min timestamp
[begin2,ends2] = find_start_end_group(id2);
begin = sort([begin1;begin2]); % concat all index corresponding to 00 or 30 min time stamps
%% main loop
k = 0;
for ci = 1:numel(begin)-1
ind_start = begin(ci);
ind_stop = begin(ci+1);
samples = ind_stop - ind_start;
if samples == 180 % only valid segments are processed
k = k+1;
data = y(ind_start:ind_stop,2:end);
mean_data{k,1} = mean(data,'omitnan');
date{k,1} = [sprintf('%02d', h(ind_start)) ':' sprintf('%02d', m(ind_start)) ':' sprintf('%02d', s(ind_start))]; % a very crude method to create the time string
end
end
% export the data
out = [date mean_data];
writecell(out,'toto.xlsx');
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function [begin,ends] = find_start_end_group(ind)
% This locates the beginning /ending points of data groups
% Important : ind must be a LOGICAL array
D = diff([0;ind(:);0]);
begin = find(D == 1);
ends = find(D == -1) - 1;
end
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