Help with iterations over large file.

조회 수: 9 (최근 30일)
gero pulido
gero pulido 2023년 12월 11일
댓글: Dyuman Joshi 2023년 12월 12일
Hello everyone, I have a huge ascii.txt wind file with the following format.
time = 0 hour
2 3 4 5 6 7
0 9 8 7 6 5
7 6 5 4 3 2
9 8 7 6 5 4
time = 3 hour
2 3 4 5 6 7
0 9 8 7 6 5
7 6 5 4 3 2
9 8 7 6 5 4
The thing is that I need to flip the rows from each block between hours, like this
time = 0 hour
9 8 7 6 5 4
7 6 5 4 3 2
0 9 8 7 6 5
2 3 4 5 6 7
time = 3 hour
9 8 7 6 5 4
7 6 5 4 3 2
0 9 8 7 6 5
2 3 4 5 6 7
I can do this for one block by
X = readlines('xwind.txt');
Y = X(2:5);
Y = flip(Y);
But I couldn’t write the loop for the entire file (4865x1 string).
Any help would be much appreciated.

채택된 답변

Dyuman Joshi
Dyuman Joshi 2023년 12월 11일
If the format of the data is homogenous through the file, try this -
in = readlines('ascii.txt')
in = 10×1 string array
"time = 0 hour" "2 3 4 5 6 7 " "0 9 8 7 6 5" "7 6 5 4 3 2" "9 8 7 6 5 4" "time = 3 hour" "2 3 4 5 6 7 " "0 9 8 7 6 5" "7 6 5 4 3 2" "9 8 7 6 5 4"
for k=2:5:size(in,1)
in(k:k+3,:) = flipud(in(k:k+3,:));
end
in
in = 10×1 string array
"time = 0 hour" "9 8 7 6 5 4" "7 6 5 4 3 2" "0 9 8 7 6 5" "2 3 4 5 6 7 " "time = 3 hour" "9 8 7 6 5 4" "7 6 5 4 3 2" "0 9 8 7 6 5" "2 3 4 5 6 7 "
  댓글 수: 2
gero pulido
gero pulido 2023년 12월 12일
Thank you! It worked perfectly
Dyuman Joshi
Dyuman Joshi 2023년 12월 12일
You're welcome!

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추가 답변 (1개)

Mathieu NOE
Mathieu NOE 2023년 12월 11일
hello
try this
I choosed to store each Y array into a cell
D=readlines('data.txt'); % read as string array
[eof] = size(D,1); % last row number (end of file)
ixP1=find(contains(D,'time')); % find the "time" line
ixP1=[ixP1 ; eof]; % add end of file line number
for k=1:numel(ixP1)-1
ind = ixP1(k)+1:ixP1(k+1)-1;
Y = str2num(char(D(ind)));
Y = flip(Y);
out{k} = Y; % store Y flipped in cell array
end

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