exponential regression functions with error in input values
이전 댓글 표시
Hi, I am trying to fit a regression model that should look like something of the form y = e^(a-bx) for some positive constants a and b. I have been perviously using the linear least squares method after taking the log of both sides and then fitting a linear model and this works. However, due to some erros in my input data this will not work for the occasion where y = 0 for obvious reasons. The issue is I need to fit an exponential line that follows the points for example [4,100], [25,50], [100,0]. This line should remain postive although the point [100,0] is where the failure arises. Any help would be greatly appreciated!
채택된 답변
추가 답변 (1개)
x = [4; 25; 100];
y = [100; 50; 0];
% objfcn = @(b,x) b(1) .* exp(b(2) - b(3).*x);
objfcn = @(b,x) exp(b(1) - b(2).*x);
[B,nres] = fminsearch(@(b)norm(y - objfcn(b,x)), rand(2,1))
xv = linspace(min(x), max(x), 50);
figure
plot(x, y, 'p')
hold on
plot(xv, objfcn(B,xv), '-r')
hold off
grid
The fitnlm function is more robust and provides statistics on the fit. Use the predict function to return the fitted curve and confidence region on the fit.
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