Trying to Solve system of 2 Equations "Unable to find explicit solution" Code In Description
조회 수: 1 (최근 30일)
이전 댓글 표시
Code pasted below, thanks in advance:
clear all;
close all;
clc;
% Solve System of Equations
syms a1 a2 a3 r_1 r_2 alpha E
a3 = (alpha*E)/(8*pi);
[sol_a1, sol_a2] = solve(2*a3*log(r_1) + (a1/(r_1)^2) + a3 + 2*a2 == 0,...
2*a3*log(r_2) + (a1/(r_2)^2) + a3 + 2*a2 == 0);
댓글 수: 0
채택된 답변
Walter Roberson
2023년 11월 4일
syms a1 a2 a3 r_1 r_2 alpha E
a3 = (alpha*E)/(8*pi);
eqn = [2*a3*log(r_1) + (a1/(r_1)^2) + a3 + 2*a2 == 0,...
2*a3*log(r_2) + (a1/(r_2)^2) + a3 + 2*a2 == 0];
partial_1 = solve(eqn(1), a1)
eqn2 = subs(eqn(2:end), a1, partial_1)
partial_2 = solve(eqn2(1), a2)
sol_a2 = partial_2
sol_a1 = subs(partial_1, a2, sol_a2)
%cross-check
subs(eqn, {a1, a2}, {sol_a1, sol_a2})
isAlways(ans)
%or... more directly...
syms a1 a2 a3 r_1 r_2 alpha E
a3 = (alpha*E)/(8*pi);
[sol_a1, sol_a2] = solve(2*a3*log(r_1) + (a1/(r_1)^2) + a3 + 2*a2 == 0,...
2*a3*log(r_2) + (a1/(r_2)^2) + a3 + 2*a2 == 0, [a1, a2])
simplify(sol_a1)
simplify(sol_a2)
댓글 수: 4
Walter Roberson
2023년 11월 6일
When you have a sym() or symfun() or symmatrix() expression, then that sort of formatting happens automatically if you are using LiveScript or MATLAB Online or MATLAB Answers. It does not happen if you are using the traditional command window (and there is no way to turn it on for the command window)
추가 답변 (1개)
Sulaymon Eshkabilov
2023년 11월 4일
편집: Sulaymon Eshkabilov
2023년 11월 4일
Note that you have six unknowns (a1, a2, r_1, r_2, alpha, E) an two equations. It is possible to get two solution type expressions using IgnoreAnalyticalConstraints option, e.g.:
syms a1 a2 r_1 r_2 alpha E
a3 = (alpha*E)/(8*pi);
SOLUTION = solve(2*a3*log(r_1) + (a1/(r_1)^2) + a3 + 2*a2 == 0,...
2*a3*log(r_2) + (a1/(r_2)^2) + a3 + 2*a2 == 0, "IgnoreAnalyticConstraints",true)
r_1 = SOLUTION.r_1
r_2 = SOLUTION.r_2
a3 = (alpha*E)/(8*pi)
댓글 수: 0
참고 항목
카테고리
Help Center 및 File Exchange에서 Number Theory에 대해 자세히 알아보기
제품
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!