Fsolve 19 state variables with matching dimensions

조회 수: 2 (최근 30일)
Gabriel McQueen
Gabriel McQueen 2023년 11월 3일
댓글: Torsten 2023년 11월 3일
I am trying to solve (or find the steady-state of) 19 state variables using 19 equations.
The error message I am getting is that for F(3) does not have matching dimensions on left and right side.
Code is provided below.
clear
clc
%initial conditions
Fc = [882e3/24,415e3/24,100e3];
S_I_0 = 40;
S_S_0 = 125;
S_ND_0 = 8;
S_NH_0 = 30;
S_NI_0 = 2;
S_NO_0 = 0.5;
S_O2_0 = 0.1; %0-0.5 g/m3
S_ALK_0 = 5;
X_I_0 = 100;
X_S_0 = 250;
X_ND_0 = 10;
X_BH_0 = 1000;
X_BA_0 = 100;
X_P_0 = 1;
X_I_0r = 200;
X_S_0r = 500;
X_ND_0r = 20;
X_BH_0r = 2;
X_BA_0r = 2;
X_P_0r = 2;
init = [S_I_0;S_S_0;S_O2_0;S_NO_0;S_NH_0;S_ND_0;S_ALK_0;
X_I_0;X_S_0;X_BH_0;X_BA_0;X_P_0;X_ND_0;
X_I_0r;X_S_0r;X_BH_0r;X_BA_0r;X_P_0r;X_ND_0r
];
x = fsolve(@(x) ASM1(Fc,x),init)
SASM1 = x(2) + x(9) + x(5);
XASM1 = x(10) + x(11);
function F = ASM1(Fc,x)
S_I = x(1);
S_S = x(2);
S_O2 = x(3);
S_NO = x(4);
S_NH = x(5);
S_ND = x(6);
S_ALK = x(7);
X_I = x(8);
X_S = x(9);
X_BH = x(10);
X_BA = x(11);
X_P = x(12);
X_ND = x(13);
X_Ir = x(14);
X_Sr = x(15);
X_BHr = x(16);
X_BAr = x(17);
X_Pr = x(18);
X_NDr = x(19);
%Flow and Volumes
V = 5000e3; %m3
%F_00 = 20*sin(t-1) + 190;
Fin = 15163e3/24; %m3
Fr = Fc(1); %m3
F = Fin + Fr;
Fw = Fc(2); %m3
%Fe = F - Fr - Fw;
Vs = 1017.36e3*3.5*2/3; %m3
%tao = 24;
%Inlet
S_S_in = 125;
S_I_in = 40;
X_S_in = 250;
X_I_in = 100;
S_ND_in = 8;
X_ND_in = 10;
S_NH_in = 30;
S_NO_in = 0.5;
S_O2_in = 0.1;
% S_NO_in = 0.5;
%O2 transfer
a_0 = 0.0018e-3;
W = Fc(3);
C_S = 10; %mg/L
kLa = a_0*W;
Qin = kLa*(C_S - S_O2);
%kinetics
Y_H = 0.67;
Y_A = 0.24;
Y_S = 0.63;
n_g = 0.8; %0.8
n_h = 0.4;
f_p = 0.08;
i_XB = 0.086;
i_XE = 0.06;
%% Kinetic Constants
%K_O2 = 0.2;
K_S = 20;
K_NO = 0.5;
K_OA = 0.4;
K_OH = 0.2;
K_NH = 1; %0.05
K_MAX = 0.34;
K_X = 0.03;
mumax_A = 0.8;
mumax_H = 6;
b_H = 0.62;
b_A = 0.132;
k_h = 3;
k_a = 0.08;
%p_7 = X_S * k_7
mu_O2 = S_O2/(K_OH+S_O2);
mu_OH = K_OH/(K_OH+S_O2);
mu_S = S_S/(K_S+S_S);
mu_NO = S_NO/(K_NO+S_NO);
mu_NH = S_NH/(K_NH + S_NH);
mu_SH = (X_S/X_BH)/(K_X+(X_S/X_BH));
mu_1 = mumax_H * mu_S * mu_O2 * X_BH;
mu_2 = mumax_H * mu_S * mu_OH * mu_NO * n_h * X_BH;
mu_3 = mumax_A * mu_NH * mu_O2 * X_BA;
mu_4 = b_H * X_BH;
mu_5 = b_A * X_BA;
mu_6 = k_a * S_ND * X_BH;
mu_7 = k_h * mu_SH *(mu_O2 + n_h * mu_OH * mu_NO)*X_BH;
mu_8 = n_g * X_ND/X_S; %p_7
%% dynamic models
F(1) = S_I_in*Fin/V - S_I*F/V;
F(2) = S_S_in*Fin/V - S_S*F/V - mu_1/Y_H - mu_2/Y_H + mu_7;
F(3) = Qin + S_O2_in*Fin/V - S_O2*F/V - (1-Y_H)/Y_H * mu_1 - (4.57 - Y_A)/Y_A * mu_3;
F(4) = S_NO_in*Fin/V - S_NO*F/V - (1 - Y_H)/(2.86*Y_H) * mu_2 + mu_3 * Y_A;
F(5) = S_NH_in*Fin/V - S_NH*F/V - i_XB* mu_1 - i_XB*mu_2 - (i_XB+1/Y_A) * mu_3 + mu_6;
F(6) = S_ND_in*Fin/V - S_ND*F/V - mu_6 + mu_8;
F(7) = - S_ALK*F/V - i_XB/14*mu_1 + ((1-Y_H)/(14*2.86*Y_H)-i_XB/14)*mu_2 - (i_XB/14 + 1/(7*Y_A))*mu_3 + mu_6/14;
F(8) = X_I_in*Fin/V + Fr*X_Ir/V - X_I*F/V;
F(9) = X_S_in*Fin/V + Fr*X_Sr/V - X_S*F/V + (1-f_p)*(mu_4+mu_5) - mu_7;
F(10) = Fr*X_BHr/V - X_BH*F/V + mu_1 + mu_2 - mu_4;
F(11) = Fr*X_BAr/V - X_BA*F/V + mu_3 - mu_5;
F(12) = Fr*X_Pr/V - X_P*F/V + f_p*(mu_4 + mu_5);
F(13) = X_ND_in*Fin/V + Fr*X_NDr/V - X_ND*F/V + (i_XB-f_p*i_XE)*(mu_4 + mu_5) - mu_8;
F(14) = F/Vs*X_I - (Fr+Fw)/Vs*X_Ir;
F(15) = F/Vs*X_S - (Fr+Fw)/Vs*X_Sr;
F(16) = F/Vs*X_BH - (Fr+Fw)/Vs*X_BHr;
F(17) = F/Vs*X_BA - (Fr+Fw)/Vs*X_BAr;
F(18) = F/Vs*X_P - (Fr+Fw)/Vs*X_Pr;
F(19) = F/Vs*X_ND - (Fr+Fw)/Vs*X_NDr;
end

채택된 답변

Torsten
Torsten 2023년 11월 3일
Rename F in this assignment:
F = Fin + Fr
F is reserved for the 19-element function vector that you return to fsolve.
  댓글 수: 3
Matt J
Matt J 2023년 11월 3일
@Gabriel McQueen since Torsten has apparently answered your question, please Accept-click the answer.
Torsten
Torsten 2023년 11월 3일
Thank you, Matt.

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