Change properties in gscatter, based on the group label
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How to set some specific properties for a specific group (i.e. marker, markersize, one specific color), let's say for group labelled as "-1", and set the same properties (i.e. marker, markersize, except for colors, that should be different) for the remaining groups, i.e. groups labelled as "1,2,3,4"?
a = [37 98 1; 35 94 1; 33 97 1; 33 99 1; 31 96 1; 30 97 1; 29 100 1; 30 94 1; 31 90 1; 28 93 1; 21 63 1; 20 61 1; 22 60 1; 24 60 1; 24 64 1; 27 62 1; 28 65 1; 27 59 1; 23 57 1; 26 56 1; 27 57 1; 29 57 1; 31 60 1; 31 61 1; 31 64 1; 32 66 1; 36 60 1; 37 56 -1; 32 56 1; 31 54 1; 27 53 1; 13 43 2; 17 42 2; 17 40 2; 19 37 2; 14 40 2; 13 42 2; 10 41 2; 10 42 2; 9 39 2; 6 40 2; 25 20 3; 24 18 3; 26 18 3; 27 19 3; 27 21 3; 29 21 3; 30 22 3; 30 23 3; 31 26 3; 33 27 3; 35 28 3; 94 11 4; 95 10 4; 97 8 4; 94 8 4; 93 8 4; 99 12 4; 97 12 4; 98 15 4; 95 14 4; 91 15 4; 92 17 4; 91 19 4; 89 19 4; 87 21 4; 89 22 4; 86 23 4; 84 25 4; 81 25 4; 80 26 4; 82 26 4; 79 29 4; 82 29 4; 83 29 4; 86 28 4; 88 25 4; 91 24 4; 93 21 4; 94 22 4; 94 19 4; 95 18 4; 97 20 4];
g = gscatter(a(:,1),a(:,2),a(:,3));
I was thinking about something like this, but I do not know how to efficiently change properties in g = gscatter:
if unique(a(:,3)) == -1
'marker'=
'markersize'=
...
elseif unique(a(:,3)) ~= -1
'marker'=
'markersize'=
...
end
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채택된 답변
dpb
2023년 11월 1일
편집: dpb
2023년 11월 1일
load carsmall
subplot(1,2,1)
gscatter(Displacement,Horsepower,Model_Year) % default appearance
subplot(1,2,2)
hGSC=gscatter(Displacement,Horsepower,Model_Year); % original but save handles
hGSC(matches({hGSC.DisplayName},'70')).Color='k'; % set year 70 group color to black
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추가 답변 (2개)
Dyuman Joshi
2023년 11월 1일
편집: Dyuman Joshi
2023년 11월 1일
You can combine the other groups as one -
a = [37 98 1; 35 94 1; 33 97 1; 33 99 1; 31 96 1; 30 97 1; 29 100 1; 30 94 1; 31 90 1; 28 93 1; 21 63 1; 20 61 1; 22 60 1; 24 60 1; 24 64 1; 27 62 1; 28 65 1; 27 59 1; 23 57 1; 26 56 1; 27 57 1; 29 57 1; 31 60 1; 31 61 1; 31 64 1; 32 66 1; 36 60 1; 37 56 -1; 32 56 1; 31 54 1; 27 53 1; 13 43 2; 17 42 2; 17 40 2; 19 37 2; 14 40 2; 13 42 2; 10 41 2; 10 42 2; 9 39 2; 6 40 2; 25 20 3; 24 18 3; 26 18 3; 27 19 3; 27 21 3; 29 21 3; 30 22 3; 30 23 3; 31 26 3; 33 27 3; 35 28 3; 94 11 4; 95 10 4; 97 8 4; 94 8 4; 93 8 4; 99 12 4; 97 12 4; 98 15 4; 95 14 4; 91 15 4; 92 17 4; 91 19 4; 89 19 4; 87 21 4; 89 22 4; 86 23 4; 84 25 4; 81 25 4; 80 26 4; 82 26 4; 79 29 4; 82 29 4; 83 29 4; 86 28 4; 88 25 4; 91 24 4; 93 21 4; 94 22 4; 94 19 4; 95 18 4; 97 20 4];
g = a(:,3);
%Change the values of other groups to a random value that is not -1
g(g~=-1) = 3;
%To different groups
n=2;
%% Define parameters (I have taken values randomly)
%Colors
clr = [0 0 1; 1 0 0];
%Marker
m = [".", "*"];
%Marker size
ms = [12.5 5];
gscatter(a(:,1), a(:,2), g, clr, m, ms)
댓글 수: 3
Dyuman Joshi
2023년 11월 1일
편집: Dyuman Joshi
2023년 11월 1일
@Sim, That can be adjusted as well -
a = [37 98 1; 35 94 1; 33 97 1; 33 99 1; 31 96 1; 30 97 1; 29 100 1; 30 94 1; 31 90 1; 28 93 1; 21 63 1; 20 61 1; 22 60 1; 24 60 1; 24 64 1; 27 62 1; 28 65 1; 27 59 1; 23 57 1; 26 56 1; 27 57 1; 29 57 1; 31 60 1; 31 61 1; 31 64 1; 32 66 1; 36 60 1; 37 56 -1; 32 56 1; 31 54 1; 27 53 1; 13 43 2; 17 42 2; 17 40 2; 19 37 2; 14 40 2; 13 42 2; 10 41 2; 10 42 2; 9 39 2; 6 40 2; 25 20 3; 24 18 3; 26 18 3; 27 19 3; 27 21 3; 29 21 3; 30 22 3; 30 23 3; 31 26 3; 33 27 3; 35 28 3; 94 11 4; 95 10 4; 97 8 4; 94 8 4; 93 8 4; 99 12 4; 97 12 4; 98 15 4; 95 14 4; 91 15 4; 92 17 4; 91 19 4; 89 19 4; 87 21 4; 89 22 4; 86 23 4; 84 25 4; 81 25 4; 80 26 4; 82 26 4; 79 29 4; 82 29 4; 83 29 4; 86 28 4; 88 25 4; 91 24 4; 93 21 4; 94 22 4; 94 19 4; 95 18 4; 97 20 4];
[g, q] = findgroups(a(:,3));
idx = q==-1;
n = numel(q);
%% Define parameters (I have taken values randomly)
%Colors
clr = hsv(n);
%Marker
m = repelem("*", 1, n);
m(idx) = ".";
%Marker size
ms = repelem(10, 1, n);
ms(idx) = 15;
gscatter(a(:,1), a(:,2), g, clr, m, ms)
Sim
2023년 11월 1일
편집: Sim
2023년 11월 1일
댓글 수: 2
dpb
2023년 11월 1일
You can always vote for others that helped; Votes aren't restricted to picking only one...and, there often are multiple ways to skin the cat or as here pieces can be taken from various solutions so the one "right" answer isn't always a palatable choice, true...
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