I know this is a rookie question but its been years since I've used MatLab. I need to use p_r,p_p,p_s to calculate p_rn,p_pn,p_sn and then use those values in place of p_r,p_p,p_s in subsequent calculations and then store them all in a matrix.

조회 수: 5 (최근 30일)
I believe I should be using a for loop with the definition of the matrix inside but the details have escaped me. Any help with this would be greatly appreciated. I would like to end up with something like this: A 101x3 matrix
[p_r, p_p, p_s;
p_rn1, p_pn1, p_sn1;
p_rn2, p_pn2, p_sn2;
...;
p_rn100, p_pn100, p_sn100]
___________________________________________________________________________________
p_r = 0.35;
p_p = 0.33;
p_s = 0.32;
T_0 = 0.39;
T_1 = 0.23;
T_2 = 0.38;
W_0 = 0.50;
W_1 = 0.29;
W_2 = 0.21;
L_0 = 0.35;
L_1 = 0.38;
L_2 = 0.27;
p_rn = (((p_r)^2)*(T_0)) + (((p_p)^2)*(T_1)) + (((p_s)^2)*(T_2)) + ((p_r)*(p_p)*((L_0)+(W_1))) + ((p_r)*(p_s)*((L_2)+(W_0))) + ((p_p)*(p_s)*((L_1)+(W_2)));
p_pn = (((p_r)^2)*(T_2)) + (((p_p)^2)*(T_0)) + (((p_s)^2)*(T_1)) + ((p_r)*(p_p)*((L_2)+(W_0))) + ((p_r)*(p_s)*((L_1)+(W_2))) + ((p_p)*(p_s)*((L_0)+(W_1)));
p_sn = (((p_r)^2)*(T_1)) + (((p_p)^2)*(T_2)) + (((p_s)^2)*(T_0)) + ((p_r)*(p_p)*((L_1)+(W_2))) + ((p_r)*(p_s)*((L_0)+(W_1))) + ((p_p)*(p_s)*((L_2)+(W_0)));
  댓글 수: 2
Jarrett White
Jarrett White 2015년 4월 17일
Trust me, I read that along with many other MatLab articles before I asked a question on here. This is just an effort to seek some insight from someone who could just get me started in the right direction.

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per isakson
per isakson 2015년 4월 17일
편집: per isakson 2015년 4월 17일
The comment caused me to deleted my first answer.
Caveat: I know next to nothing about Game Theory
Assumption: The expressions in the question define how the probabilities, P(n), are calculated based on their previous values, P(n-1). If so, no recursion is needed.
Try
>> P = cssm( 1/3+randn(1,3)/200 ); P(1:5,:)
ans =
0.3337 0.3273 0.3278
0.3263 0.3261 0.3252
0.3186 0.3187 0.3185
0.3045 0.3045 0.3045
0.2781 0.2781 0.2781
>> plot( P )
>> P = cssm( 1/3+randn(1,3)/200 ); P(1:5,:)
ans =
0.3333 0.3410 0.3295
0.3349 0.3367 0.3359
0.3383 0.3384 0.3385
0.3435 0.3435 0.3436
0.3541 0.3541 0.3541
where
function P = cssm(P0)
P = nan( 101, 3 ); % allocate memory
p_r = 0.35; p_p = 0.33; p_s = 0.32;
T_0 = 0.39; T_1 = 0.23; T_2 = 0.38;
W_0 = 0.50; W_1 = 0.29; W_2 = 0.21;
L_0 = 0.35; L_1 = 0.38; L_2 = 0.27;
if nargin == 0
P(1,:) = [ p_r, p_p, p_s ];
else
P(1,:) = P0;
end
for n = 2 : size( P, 1 )
P(n,1) = ((P(n-1,1))^2)*(T_0) ...
+ ((P(n-1,2))^2)*(T_1) ...
+ ((P(n-1,3))^2)*(T_2) ...
+ ((P(n-1,1))*(P(n-1,2))*((L_0)+(W_1))) ...
+ ((P(n-1,1))*(P(n-1,3))*((L_2)+(W_0))) ...
+ ((P(n-1,2))*(P(n-1,3))*((L_1)+(W_2))) ;
P(n,2) = ((P(n-1,1))^2)*(T_2) ...
+ ((P(n-1,2))^2)*(T_0) ...
+ ((P(n-1,3))^2)*(T_1) ...
+ ((P(n-1,1))*(P(n-1,2))*((L_2)+(W_0))) ...
+ ((P(n-1,1))*(P(n-1,3))*((L_1)+(W_2))) ...
+ ((P(n-1,2))*(P(n-1,3))*((L_0)+(W_1))) ;
P(n,3) = ((P(n-1,1))^2)*(T_1) ...
+ ((P(n-1,2))^2)*(T_2) ...
+ ((P(n-1,3))^2)*(T_0) ...
+ ((P(n-1,1))*(P(n-1,2))*((L_1)+(W_2))) ...
+ ((P(n-1,1))*(P(n-1,3))*((L_0)+(W_1))) ...
+ ((P(n-1,2))*(P(n-1,3))*((L_2)+(W_0))) ;
end
end
  댓글 수: 1
Jarrett White
Jarrett White 2015년 4월 17일
Thanks per isakson! What these p_r, p_p, and p_s represent are starting probabilities for strategies in a symmetric zero sum game. I am doing an doing an analysis on conditional responses and the cyclic flow of strategies in discrete time. The p_rn, p_pn, and p_sn, where n=time from 0 to 100, represent the new probabilities of using strategies after each round. So I would like to use p_r to find p_r1, p_r1 to find p_r2, and so on. I guess its a sort of recursive function. Then I need to store these values to construct a plot of their behavior. I'm just not entirely sure of what the correct syntax would be to represent the recursive nature in the loop. I feel like the answer lies in the construction of my definition of p_rn, p_pn, and p_sn.

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