필터 지우기
필터 지우기

sound normalization made distortion bigger

조회 수: 3 (최근 30일)
L
L 2023년 10월 26일
댓글: Walter Roberson 2023년 10월 30일
Hi.. I normalized some wav files using the following code. The reason to normalize is that I need the sound to have the same power.
When I played it in low volume everything is okay. But when I get the volume up, the sounds get terrible and distorted.
What is going on?
data_dir = sprintf('%s/data/audio_wav/Uniq_uncued',root_dir);
% Get a list of all files in the directory with the .wav extension.
files = dir(sprintf('%s/*.wav', data_dir)); %we only want control for cues.
%% Loop through each file
for idx = 1:length(files)
% read file
file = sprintf('%s/%s', data_dir, files(idx).name);
% get sound
[y,Fs] = audioread(file);
% get sound power
signalPower = sum(y.^2,1)/size(y,1);
%playsound
soundsc(y,Fs); pause(3);
%normalize power (L2 norm normalization)
new_y = y ./ sqrt( signalPower )/10;
% check sound power
new_signalPower = sum(new_y.^2,1)/size(new_y,1);
%playsound
soundsc(new_y,Fs); pause(3);
% This part of the code is trying to prevent the distortion (got it from a post, but it is not working)
yInt = new_y * 32768;
yInt(yInt == 32768) = 32767;
% save
[pathstr, name, ext] = fileparts(file);
audiowrite(sprintf('%s/%s_norm.wav', data_dir, name), yInt, Fs);
end
Thanks
  댓글 수: 1
L
L 2023년 10월 26일
I think that the sound is being clipped when saving using audiowrite. That is the problem.
Just don't know how to solve it.

댓글을 달려면 로그인하십시오.

채택된 답변

Walter Roberson
Walter Roberson 2023년 10월 26일
yInt = new_y * 32768;
You need to convert to int16 after you zap the 32768.
You could consider using im2int16 instead of your current steps.
  댓글 수: 4
L
L 2023년 10월 30일
Thanks for your answer.
I actually solved the problem by using BitsPerSample as 64.
Walter Roberson
Walter Roberson 2023년 10월 30일
yes, that should work, as it would trigger saving in double precision. However, the code
yInt = new_y * 32768;
strongly implies that you are converting to unsigned 16 bit integer.
When you read in the file with audioread(), it is likely (but not certain) that the "information content" is only 16 bits per sample. You do a computation to arrive at a scalar and divide all of the samples by that same scalar: the "information content" of each scalar would continue to be 16 bits. But you are writing out the results as 64 bits -- it is a waste of space.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Measurements and Spatial Audio에 대해 자세히 알아보기

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by