code for this type of GROUP bar graph?

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Francesco Marchione
Francesco Marchione 2023년 10월 4일
댓글: Anton Kogios 2023년 10월 6일
I would like to plot this graph with font in LATEX.
The data are just numbers (known from experiments).
In addition, I would also like to add the error (standard deviation) on each bar (known number).
Can you help me in writing the code?
Thanks a lot!

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Anton Kogios
Anton Kogios 2023년 10월 5일
This isn't exactly the same as your plot, but I hope it helps. If you want a patterned fill on your bars, you can check out Hatchfill2 (see some examples here). You may have to convert it to a histogram or play around with the bars if you don't want space between the bars.
% Generate data
y = zeros(5,4);
for i = 1:5
y(i,:) = (6-i)*10 + randi(10,[1,4]);
end
% Plot bar graph
figure(1);clf
b = bar(1:5,y,'FaceAlpha',0.55);
b(1).FaceColor = [0.9290 0.6940 0.1250];
b(2).FaceColor = [0.4660 0.6740 0.1880];
b(3).FaceColor = [0.4940 0.1840 0.5560];
b(4).FaceColor = [1 1 0];
% Axis ticks
xticklabels({'R','200','400','600','800'})
a = gca;
a.TickLabelInterpreter = 'latex';
a.FontSize = 12;
% Labels and legend
xlabel('Temperature in $^\circ$C','Interpreter','latex','FontSize',13)
ylabel('Compressive Strength (MPa)','Interpreter','latex','FontSize',13)
legend({'GPC (Control)','10\% GP-A','20\% GP-A','30\% GP-A'}, ...
'Interpreter','latex','FontSize',12)
% Errorbars
hold on
sd = randi(3,5,4);
errorbar([b.XEndPoints],[b.YEndPoints],sd(:), ...
'Color','k','LineStyle','none','HandleVisibility','off')
hold off
  댓글 수: 2
Francesco Marchione
Francesco Marchione 2023년 10월 6일
Thank you so much!
Just one more question (I am very novice, please help me)...
How can I write in order to report precise values both for data and errors?
E.g., I have
R=(45, 55, 49, 70) and errors +-5; +-2; +-1; +-8
200=(75, 49, 49, 60) and errors +-5; +-2; +-1; +-8
400=(64, 37, 49, 50) and errors +-5; +-2; +-1; +-8
600=(42, 35, 49, 40) and errors +-5; +-2; +-1; +-8
800=(20, 20, 10, 9) and errors +-5; +-2; +-1; +-8
I would like to put my precise numbers instead of a function given by the cyle FOR.
Thank you for your patience.
Anton Kogios
Anton Kogios 2023년 10월 6일
No worries! You should be able to figure this out yourself if you look at what y and sd look like by removing the semicolon at the end of the line. You can also tell by the size of the arrays.
To point you in the right direction, both y and sd have 5 rows (one for each of the groups) and 4 columns (one for each element in the group). So, in your case something like this should work:
y = [45,55,49,70; % R
75,49,49,60; % 200
64,37,49,50; % 400
42,35,49,40; % 600
20,20,10,9]; % 800
sd = repmat([5,2,1,8],[5,1]);

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