Convert the hexadecimal representation of a binary double-precision number back into a double

How can I convert a double-precision hexadecimal back into a double?

That is, given s, created from the double x as such:

   s = sprintf('%bx',x)

How can I recover x?

Answer 1

[Fangjun Jiang]

>> x=rand
x =
   0.126986816293506
>> s = sprintf('%bx',x)
s =
3fc0411a9f807b7c
>> y=hex2num(s)
y =
   0.126986816293506

[Matthew Simoneau]

That's it! I tried this and thought it wasn't working, but I had previously set "format hex". Thanks.