Why is the graph in this code becoming distorted?

조회 수: 7 (최근 30일)
영택 조
영택 조 2023년 9월 19일
편집: Dyuman Joshi 2023년 9월 19일
%% This is the code.
n=101;
nstep=100;
long=10.0;
h=long/(n-1);
dt=0.05;
D=0.05;
f=zeros(n,1);
y=zeros(n,1);
time=0.0;
for i=1:n
f(i)=0.5*sin(2*pi*h*(i-1));
end
for m=1:nstep
plot(f,'linewidth',2);
axis([1 n -2 2])
y=f;
for ii=2:n-1
f(ii)=y(ii)-0.5*(dt/h)*(y(ii+1)-y(ii-1)+D*(dt/h^2)*(y(ii+1)-2*y(ii)+y(ii-1)));
end
f(n)=y(n)-0.5*(dt/h)*(y(2)-y(n-1))+D*(dt/h^2)*(y(2)-2*y(n)+y(n-1));
time=time+dt;
title(sprintf('time = %3.2f',time))
pause(0.2)
end
As a result of running this code, the graph becomes distorted from the right end and stretched as 'time' increases. Is there something wrong that is causing this?

채택된 답변

Mathieu NOE
Mathieu NOE 2023년 9월 19일
hello
maybe this ? I simply corrected one of your equation (looking at the one that follows , assumming the second was correct ) because there is a difference where you put your parenthesis
%% This is the code.
n=101;
nstep=100;
long=10.0;
h=long/(n-1);
dt=0.05;
D=0.05;
f=zeros(n,1);
y=zeros(n,1);
time=0.0;
i=1:n;
f=0.5*sin(2*pi*h*(i-1));
for m=1:nstep
plot(f,'linewidth',2);
axis([1 n -2 2])
y=f;
for ii=2:n-1
% f(ii)=y(ii)-0.5*(dt/h)*(y(ii+1)-y(ii-1)+D*(dt/h^2)*(y(ii+1)-2*y(ii)+y(ii-1)));
f(ii)=y(ii)-0.5*(dt/h)*(y(ii+1)-y(ii-1))+D*(dt/h^2)*(y(ii+1)-2*y(ii)+y(ii-1)); % correction based on the equation 2 lines below
end
f(n)=y(n)-0.5*(dt/h)*(y(2)-y(n-1))+D*(dt/h^2)*(y(2)-2*y(n)+y(n-1));
time=time+dt;
title(sprintf('time = %3.2f',time))
pause(0.2)
end

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