Elevar un polinomio al cuadrado

조회 수: 13 (최근 30일)
Johan
Johan 2023년 9월 9일
댓글: Johan 2023년 9월 9일
Tengo este polinomio el cual contiene números racionales:
g = [3/2 -1/4 -1/3];
secondT = poly2sym(g); % g pero como polinomio
Lo necesito elevar al cuadrado, pero no encuetro ningúna forma para hacer esto. O sea, puedo elevar a g al cuadrado sin ningún problema:
disp(g.^2);
Pero necesito multiplicar los exponentes de la variable (x). Cuando trato de elevar secondT me da este resultado:
(x/4 - (3*x^2)/2 + 1/3)^2
  댓글 수: 1
John D'Errico
John D'Errico 2023년 9월 9일
편집: John D'Errico 2023년 9월 9일
Sorry, that my high school Spanish is far too long out of date. :( Google translate:
I have this polynomial which contains rational numbers:
g = [3/2 -1/4 -1/3];
secondT = poly2sym(g); % g but as a polynomial
I need to square it, but I can't find any way to do this. That is, I can square g without any problem:
disp(g.^2);
But I need to multiply the exponents of the variable (x). When I try to raise secondT it gives me this result:
(x/4 - (3*x^2)/2 + 1/3)^2

댓글을 달려면 로그인하십시오.

채택된 답변

John D'Errico
John D'Errico 2023년 9월 9일
편집: John D'Errico 2023년 9월 9일
Easy enough.
g = [3/2 -1/4 -1/3];
gsym = poly2sym(g);
gsym^2
ans = 
And as you know, it squares the polynomial, but does not expand it. Nothing stops you from using the symbolic toolbox however.
expand(gsym^2)
ans = 
Could you also have done this without using the symbolic toolbox at all? Well, yes, using conv you can multiply polynomials in double precision rthmetic. But then you will be stuck with doubles, not exact fractional coefficients. If you don't push things too far though, you could have done this...
format rat
conv(g,g)
ans =
9/4 -3/4 -15/16 1/6 1/9
And format rat comes to save the day. Again, don't push things too far, as it has limits.
  댓글 수: 4
Walter Roberson
Walter Roberson 2023년 9월 9일
sympref('PolynomialDisplayStyle', 'descend');
syms x c2 c1 c0
gsym = c2*x^2 + c1*x + c0
gsym = 
gsym^2
ans = 
expand(ans)
ans = 
so the -(3*x^3)/4 is 2 * (3/2) * (-1/4)
Johan
Johan 2023년 9월 9일
Thanks man

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Spline Postprocessing에 대해 자세히 알아보기

제품


릴리스

R2023a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by