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MATLAB not computing integral of an infinite integral

조회 수: 1 (최근 30일)
AD
AD 2023년 8월 23일
편집: Dyuman Joshi 2023년 8월 28일
I am trying to compute the integral of the function. However, MATLAB is unabble to compute it. I havetried numerical integration function 'integral' with no results. Can someone please tell how to proceed with this? Thanks in advance!
P_l=50;
v=0.1;
k=15;
Tm=1;
T0=300;
alpha=3.75*10^(-6);
E= 190*10^9;
nu=0.3;
syms x z x_prime z_prime t dT_dx dT_dz;
xm=x-x_prime;
zp=z+z_prime;
zm=z-z_prime;
% Define the terms
T=(P_l*exp(-((sqrt((x-v*t)^2 + (z)^2) + (x-v*t)))/(2*alpha)))/(4*3.14*k*sqrt((x-v*t)^2 + (z)^2)) +T0;
dT_dx=diff(T,x);
dT_dx_prime=subs(dT_dx,[x,z],[x_prime,z_prime]);
dT_dz=diff(T,z);
dT_dz_prime=subs(dT_dz,[x,z],[x_prime,z_prime]);
Gxh=@(xm,zm,zp) (1/(4*pi))*(3*(xm/(xm^2 + zp^2)) + 2*(xm*zm^2/(xm^2 +zm^2)^2))-(1/pi)*(3*(xm*(z_prime*zp + xm^2)/(xm^2 + zp^2)^2)-(3*(z_prime)^2*xm*zp*2 +xm^3*(4*z_prime^2 + 6*z*z_prime + z^2 + xm^2))/(xm^2+zp^2)^3);
Gxv= @(xm,zm,zp) (-1/(4*pi))*((zp/(xm^2 + zp^2))+ 2*((xm^2*zm/(xm^2+zm^2)^2)-(xm^2*zm)/(xm^2 +zm^2)^2))-(1/(2*pi)*(2*(zp/(xm^2 + zp^2)))-((2*z-z_prime)*(zp^2-xm^2)/(xm^2+zp^2)^2)+(2*z*z_prime*zp*(3*xm^2-zp^2))/(xm^2+zp^2)^3);
p= @(t) P_l*exp(-(-v*t)/2*alpha)/(4*pi*k*(-v*t));
term1 = -(alpha * E / (1 - 2*v)) * ...
int(int((Gxh * dT_dx + Gxv * dT_dz), x_prime, -inf, inf), z_prime, 0, inf);
term2 = (2 * z) / pi * ...
int(p(t) * (t - x)^2 / ((t - x)^2 + z^2)^2,t, -inf, inf);
term3 = -(alpha * E * T) / (1 - 2*v);
% Combine the terms
Sigma = term1 + term2 + term3;
% You can simplify Sigma if desired
simplifiedSigma = simplify(Sigma);
substitutedSigma=subs(simplifiedSigma,[t,x,z],[0,0.001,0]);

채택된 답변

Dyuman Joshi
Dyuman Joshi 2023년 8월 23일
Convert the symbolic functions to function handles, and use numerical integrals -
P_l=50;
v=0.1;
k=15;
Tm=1;
T0=300;
alpha=3.75*10^(-6);
E= 190*10^9;
nu=0.3;
syms x z x_prime z_prime t dT_dx dT_dz;
xm=x-x_prime;
zp=z+z_prime;
zm=z-z_prime;
% Define the terms
T=(P_l*exp(-((sqrt((x-v*t)^2 + (z)^2) + (x-v*t)))/(2*alpha)))/(4*3.14*k*sqrt((x-v*t)^2 + (z)^2)) +T0;
dT_dx=diff(T,x);
dT_dx_prime=subs(dT_dx,[x,z],[x_prime,z_prime]);
dT_dz=diff(T,z);
dT_dz_prime=subs(dT_dz,[x,z],[x_prime,z_prime]);
Gxh= (1/(4*pi))*(3*(xm/(xm^2 + zp^2)) + 2*(xm*zm^2/(xm^2 +zm^2)^2))-(1/pi)*(3*(xm*(z_prime*zp + xm^2)/(xm^2 + zp^2)^2)-(3*(z_prime)^2*xm*zp*2 +xm^3*(4*z_prime^2 + 6*z*z_prime + z^2 + xm^2))/(xm^2+zp^2)^3);
Gxv= (-1/(4*pi))*((zp/(xm^2 + zp^2))+ 2*((xm^2*zm/(xm^2+zm^2)^2)-(xm^2*zm)/(xm^2 +zm^2)^2))-(1/(2*pi)*(2*(zp/(xm^2 + zp^2)))-((2*z-z_prime)*(zp^2-xm^2)/(xm^2+zp^2)^2)+(2*z*z_prime*zp*(3*xm^2-zp^2))/(xm^2+zp^2)^3);
p= P_l*exp(-(-v*t)/2*alpha)/(4*pi*k*(-v*t));
%Convert to a function handle
T = matlabFunction(T);
p = matlabFunction(p);
fun = matlabFunction(Gxh * dT_dx + Gxv * dT_dz);
%Define terms as funciton handles
term1 = @(t,x,z) integral2(@(x_prime,z_prime) fun(t,x,z,x_prime,z_prime),-inf,inf,0,inf);
term2 = @(x,z) integral(@(t,x,z) (2.*z)./pi*(p(t).*(t - x).^2./((t - x).^2 + z^2).^2), t, -inf, inf);
term3 = @(t,x,z) -(alpha * E * T(t,x,z)) / (1 - 2*v);
Sigma = term1(0,0.001,0) + 0 + term3(0,0.001,0)
Sigma = -2.6719e+08
  댓글 수: 2
AD
AD 2023년 8월 23일
Heyy..I am getting an error while calculating the term 2. ALso, there are no changes in the result for different t,x,z values.
Dyuman Joshi
Dyuman Joshi 2023년 8월 28일
편집: Dyuman Joshi 2023년 8월 28일
I corrected the error for term2.
P_l=50;
v=0.1;
k=15;
Tm=1;
T0=300;
alpha=3.75*10^(-6);
E= 190*10^9;
nu=0.3;
syms x z x_prime z_prime t dT_dx dT_dz;
xm=x-x_prime;
zp=z+z_prime;
zm=z-z_prime;
% Define the terms
T=(P_l*exp(-((sqrt((x-v*t)^2 + (z)^2) + (x-v*t)))/(2*alpha)))/(4*3.14*k*sqrt((x-v*t)^2 + (z)^2)) +T0;
dT_dx=diff(T,x);
dT_dx_prime=subs(dT_dx,[x,z],[x_prime,z_prime]);
dT_dz=diff(T,z);
dT_dz_prime=subs(dT_dz,[x,z],[x_prime,z_prime]);
Gxh= (1/(4*pi))*(3*(xm/(xm^2 + zp^2)) + 2*(xm*zm^2/(xm^2 +zm^2)^2))-(1/pi)*(3*(xm*(z_prime*zp + xm^2)/(xm^2 + zp^2)^2)-(3*(z_prime)^2*xm*zp*2 +xm^3*(4*z_prime^2 + 6*z*z_prime + z^2 + xm^2))/(xm^2+zp^2)^3);
Gxv= (-1/(4*pi))*((zp/(xm^2 + zp^2))+ 2*((xm^2*zm/(xm^2+zm^2)^2)-(xm^2*zm)/(xm^2 +zm^2)^2))-(1/(2*pi)*(2*(zp/(xm^2 + zp^2)))-((2*z-z_prime)*(zp^2-xm^2)/(xm^2+zp^2)^2)+(2*z*z_prime*zp*(3*xm^2-zp^2))/(xm^2+zp^2)^3);
p= P_l*exp(-(-v*t)/2*alpha)/(4*pi*k*(-v*t));
%Convert to a function handle
T0 = matlabFunction(T);
p = matlabFunction(p);
f = Gxh * dT_dx + Gxv * dT_dz;
fun = matlabFunction(f);
%Define terms as function handles
term1 = @(t,x,z) integral2(@(x_prime,z_prime) fun(t,x,z,x_prime,z_prime), -inf, inf, 0, inf);
term2 = @(x,z) integral(@(t) (2.*z)./pi*(p(t).*(t - x).^2./((t - x).^2 + z^2).^2), -inf, inf);
term3 = @(t,x,z) -(alpha * E * T0(t,x,z)) / (1 - 2*v);
"ALso, there are no changes in the result for different t,x,z values."
Because the result is dominated by term3, in which there is not much change w.r.t values
format long
%t x z values
%0 0.001 0
term1(0,0.001,0)
ans =
-3.453931570108182e-107
term2(0.001,0)
ans =
0
term3(0,0.001,0)
ans =
-2.671874999999999e+08
%-0.5 0 5
term1(-0.5,0,5)
ans =
0
term2(0,5)
ans =
-4.973591972400049e-07
term3(-0.5,0,5)
ans =
-2.671874999999999e+08
%-5e3 0 0
term1(-5e3,0,0)
ans =
0
term2(0,0)
ans =
0
term3(-5e3,0,0)
ans =
-2.671874999999999e+08

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