How can i solve initial value ordinary differential equation using matlab ??

조회 수: 6 (최근 30일)
I want to solve four differtial equation and these are shown in picture. Here u,s,p,r are dependent variable and t is the independent variable. W and a are the constant (values are 154 and 44.5 degree). t is the independent variable and varies from 0 to 180 degree. initial condition are u0 = 0.10, so = 0.2025, p0 = 1.4706, r0 = 2.2449.
  댓글 수: 5
Surendra Ratnu
Surendra Ratnu 2023년 8월 21일
They are not cross product. It is simply multiplication and d/dt denote the differtiation with respect to t. I attached a picture for the equation. here is u s are the two differtent variable.
Bruno Luong
Bruno Luong 2023년 8월 21일
Some obvious mixe and match unit : sin and cos take argument in radian not in degree

댓글을 달려면 로그인하십시오.

채택된 답변

Bruno Luong
Bruno Luong 2023년 8월 21일
편집: Bruno Luong 2023년 8월 21일
I change integration variables to v=u*s and w=u^2*s;
This should work (you need to sort out the discrepency of unit, speccially for t)
W = 154;
a = deg2rad(44.5);
u0 = 0.10;
s0 = 0.2025;
p0 = 1.4706;
r0 = 2.2449;
v0 = u0*s0;
w0 = u0^2*s0;
y0 = [v0;w0;p0;r0];
sol = ode45(@(t,y) odefun(t,y,a,W),[0 pi],y0);
t = sol.x;
y = sol.y;
v = y(1,:);
w = y(2,:);
p = y(3,:);
r = y(4,:);
u = w./v;
s = v./u;
tdeg = rad2deg(t)
tdeg = 1×13
0 7.9475 21.1057 35.2541 53.2541 71.2541 89.2541 107.2541 125.2541 143.2541 158.1571 171.0410 180.0000
figure
subplot(2,2,1); plot(tdeg, u); xlabel('tdeg'); ylabel('u')
subplot(2,2,2); plot(tdeg, s); xlabel('tdeg'); ylabel('s')
subplot(2,2,3); plot(tdeg, p); xlabel('tdeg'); ylabel('p')
subplot(2,2,4); plot(tdeg, r); xlabel('tdeg'); ylabel('r')
function dydt = odefun(t, y, a, W)
%v = y(1); % u*s
w = y(2); % u^2*s
p = y(3);
r = y(4);
sina = sin(a);
cosacost = cos(a).*cos(t);
c = sina^3./(4*(1+cosacost).^2);
dvdt = c;
dwdt = c.*cos(p);
dpdt = (2*r/W - c*sin(p).^2) ./ (w.*sin(p)) - 1;
drdt = t ./ tan(p);
dydt = [dvdt; dwdt; dpdt; drdt];
end

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Programming에 대해 자세히 알아보기

제품


릴리스

R2023a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by