hello,when i run the following script,error happens, any one knows what the root reason, following are the script.
sfnew
rt = sfroot;
ch = find(rt,'-isa','Stateflow.Chart');
st = Stateflow.State(ch);
view(st)
j1 = Stateflow.Junction(ch);
j1.Position.Radius = 16.18;
j1.Position.Center = [31.41 27.18];
j2 = Stateflow.Junction(ch);
j2.Position.Radius = 16.18;
j2.Position.Center = [62.41 27.18];
transition = Stateflow.Transition(ch);
transition.Source = j1;
transition.Destination = j2;
transition.LabelString = '{xx;yy;zz;}';

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Fangjun Jiang
Fangjun Jiang 2023년 8월 14일
No error in R2022b. What is the error message?
wenchao zhang
wenchao zhang 2023년 8월 14일
ok,thanks,may be it is caused by lost the state flow license, tomorrow i will check again. may be some command not supported in 2019a, not sure

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도움말 센터File Exchange에서 Decision Logic에 대해 자세히 알아보기

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R2019a

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2023년 8월 14일

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2023년 8월 14일

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