Matlab code not computing
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is anyone able to review my code and tell me why its not outputing correcrtly when i run it im not sure what errors i have
clear
p=-1;
z=-5;
K = 0.05:0.001:100;
a=K;
b=2*K.^2-p*K;
c=-z*K.^2;
root1 = (-b + sqrt(b.^2 - 4.*a.*c))./(2.*a);
root2 = (-b - sqrt(b.^2 - 4.*a.*c))./(2.*a);
root = root1;
K_corresponding = K;
decay_rate = real;
fprintf('The maximal imaginary part is: %f\n', max_imag_part);
fprintf('The corresponding value of K is: %f\n', K_corresponding);
fprintf('The decay rate is: %f\n', decay_rate);
figure
plot(real(root), imag(root));
scatter[real(root(max_index)], imag[root(max_index)], 'red'; 'filled');
xlabel('Real Part');
ylabel('Imaginary Part');
title('Root Locus Plot');
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Alan Stevens
2023년 7월 18일
The use of square brackets in the scatter function is not the only problem! Are you looking for something like this?
p=-1;
z=-5;
K = 0.05:0.001:100;
a=K;
b=2*K.^2-p*K;
c=-z*K.^2;
root1 = (-b + sqrt(b.^2 - 4.*a.*c))./(2.*a);
root2 = (-b - sqrt(b.^2 - 4.*a.*c))./(2.*a);
root = root1;
iroot = imag(root);
maximag = max(iroot);
max_index = find(iroot == maximag);
K_corresponding = K(max_index);
decay_rate = real(root(max_index));
fprintf('The maximal imaginary part is: %f\n',maximag);
fprintf('The corresponding value of K is: %f\n', K_corresponding);
fprintf('The decay rate is: %f\n', decay_rate);
figure
plot(real(root), imag(root));
hold on
scatter(real(root(max_index)), imag(root(max_index)), 'red', 'filled');
xlabel('Real Part');
ylabel('Imaginary Part');
title('Root Locus Plot');
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Image Analyst
2023년 7월 21일
If this Answer solves your original question, then could you please click the "Accept this answer" link to award the answerer with "reputation points" for their efforts in helping you? They'd appreciate it. Thanks in advance. 🙂 Note: you can only accept one answer (so pick the best one) but you can click the "Vote" icon for as many Answers as you want. Voting for an answer will also award reputation points.
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