Make two vectors equal with zero inserted in the missed location values of the small vector

I have two vectors one small and the another is larger. I want to check element by element and if there is an element in first vector does not equal to the corresponding element in the second vector, put zero at this missed location in small vector, so as finally the small vector will have the same size of the first vector, but with zero padded in the missing element positions.

for example

V1=[1,2,3,4,1,2,3,4];
V2=[1,2,4,1,3,4];

How to get V2 with this [1,2,0,4,1,0,3,4]

Answer 1

[Matt J]

V1=[1,2,3,4,1,2,3,4];
V2=[1,2,4,1,3,4];

n1=length(V1);
for i=1:n1
 
    if i>length(V2)
        
       V2(end+1:n1)=0; break
       
    elseif V1(i)~=V2(i) 

        V2=[V2(1:i-1),0,V2(i:end)];
        V2=V2(1:min(end,n1)); 
        
    end
 
end


V1

V1 = 1×8

1 2 3 4 1 2 3 4

V2

V2 = 1×8

1 2 0 4 1 0 3 4

[bassant tolba]

Thank you very much. It works

Answer 2

[Walter Roberson]

for loop. No point trying to be smart about it, if you can guarantee that the second one is always a series of sub-sequences of the first.

If you were trying to find the "best" match between two sequences that have differences in places, then that would fall into the category of "sequence alignment", and there would be multiple algorithms for that; some of them are mentioned at https://www.mathworks.com/help/bioinfo/sequence-alignment.html

[bassant tolba]

Thank you very much for your help