Color's histogram and histogram's comparasion.

조회 수: 5 (최근 30일)
Pol
Pol 2023년 5월 8일
댓글: Image Analyst 2023년 5월 9일
I've been given a set of images showing different football equipements (t-shirts) with different colors. The idea is, for each image, compute its histogram of RGB colors with N bins, and once computed, compute the similiraty between histograms (using either Chi-Square method or Euclidean distance). I am struggling doing both tasks and I am desperate, so I really hope someone could help me. I'll leave the two functions used down here:
% Histogram computation
function [hist_3d] = Calcular_Histograma_rg(image)
bins = 9;
R = image(:,:,1);
G = image(:,:,2);
B = image(:,:,3);
hist_3d = zeros(bins, bins, bins);
[n m] = size(R);
for i = 1:n
for j = 1:m
r = R(i, j)/ (256/bins) + 1;
b = B(i, j)/ (256/bins) + 1;
g = G(i, j)/ (256/bins) + 1;
if (r > bins)
r = r - 1;
end
if (b > bins)
b = b - 1;
end
if (g > bins)
g = g - 1;
end
hist_3d(r, b, g) = hist_3d(r, b, g) + 1;
end
end
hist_3d = hist_3d ./ (n*m);
hist_3d = hist_3d ./ (n*m);
end
% Similarity using euclidean distance computation
function [similarity] = Calcular_Similitud_rg(hist_org,hist)
[n, m] = size(hist_org);
dist = 0;
for i=1:n
for j=1:m
aux = (hist_org(i, j) - hist(i, j));
dist = dist + (aux*aux);
end
end
similarity = sqrt(dist);
end
  댓글 수: 1
Pol
Pol 2023년 5월 8일
Maybe it is better to do it in HSV space. Give the appropiate change as you want.

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답변 (2개)

Image Analyst
Image Analyst 2023년 5월 9일
You're going to have to round r, g, and b because they're not integers and can't be used as indexes.
Don't use image as the name of your variable since it's already a built-in function.
Have you thought about what to do if the two images are not the same size? Maybe you want to normalize the histograms.

LeoAiE
LeoAiE 2023년 5월 9일
Maybe you have implemented the histogram computation and similarity calculation using Euclidean distance. there are a few modifications needed. First, in the Calcular_Histograma_rg function, you have duplicated the normalization step, which should only be done once. Second, you need to adapt the Calcular_Similitud_rg function to handle 3D histograms.
% Histogram computation
function [hist_3d] = Calcular_Histograma_rg(image)
bins = 9;
R = image(:,:,1);
G = image(:,:,2);
B = image(:,:,3);
hist_3d = zeros(bins, bins, bins);
[n, m] = size(R);
for i = 1:n
for j = 1:m
r = floor(R(i, j) / (256/bins)) + 1;
b = floor(B(i, j) / (256/bins)) + 1;
g = floor(G(i, j) / (256/bins)) + 1;
hist_3d(r, b, g) = hist_3d(r, b, g) + 1;
end
end
hist_3d = hist_3d ./ (n * m);
end
% Similarity using Euclidean distance computation
function [similarity] = Calcular_Similitud_rg(hist_org, hist)
[n, m, p] = size(hist_org);
dist = 0;
for i = 1:n
for j = 1:m
for k = 1:p
aux = (hist_org(i, j, k) - hist(i, j, k));
dist = dist + (aux * aux);
end
end
end
similarity = sqrt(dist);
end
image1 = imread('image1.jpg');
image2 = imread('image2.jpg');
hist1 = Calcular_Histograma_rg(image1);
hist2 = Calcular_Histograma_rg(image2);
similarity = Calcular_Similitud_rg(hist1, hist2);
  댓글 수: 1
Image Analyst
Image Analyst 2023년 5월 9일
Don't use image as the name of your variable since it's already a built-in function.

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