Index exceeds matrix dimensions

I've got a problem and because of my bad knowledge of matlab, it would be great if someone know the solution for this problem.
arr = {'01', '02', '03', '04'};
ldir = '/data/.....'
cond= {Forstats_1PLhann.mat};
savedir = ldir;
for i= 1:11;
display (sprintf('analysing subject....%s,arr{i}));
subjectdir=strcat(ldir, 'Tsbj_', arr{i},'/');
load(strcat(subjectdir,cond {1}));
data{1,i} = ft_freqdescriptives ([], PLhann);
clear PLhann
end;
cond= {Forstats3_PLhann.mat'};
for i = 12:22
display (sprintf('analysing subject....%s,arr{i}));
subjectdir=strcat(ldir, 'Tsbj_', arr{i},'/');
load(strcat(subjectdir,cond {1}));
data{1,i} = ft_freqdescriptives ([], PLhann);
clear PLhann end;
ERROR: Index exceeds matrix dimensions

댓글 수: 2

Ilham Hardy
Ilham Hardy 2015년 4월 3일
Please post the complete error message (do not trim the error message).
Rena Berman
Rena Berman 2018년 1월 17일
(Answers Dev) Restored edit

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답변 (1개)

Ingrid
Ingrid 2015년 4월 3일
편집: Ingrid 2015년 4월 3일

0 개 추천

your array only contains four elements (first line of your code) in your loop you are trying to acces arr{i} where i goes from 1:11 this gives you the error message that the index exceeds matrix dimensions when the loop goes to i=5 because arr{5} does not exist so you have to change
for i = 1:4
OR define
arr = {'01', '02', '03', '04','05','06','07','08','09','10','11'};
depending on which one is applicable for your case

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도움말 센터File Exchange에서 Matrix Indexing에 대해 자세히 알아보기

질문:

2015년 4월 3일

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2018년 1월 17일

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