Assign a value to a dictionary of dictionary

조회 수: 27 (최근 30일)
Ajay Reddy
Ajay Reddy 2023년 5월 6일
댓글: chicken vector 2023년 5월 6일
Hello everyone,
I have something like:
x = dictionary(dictionary()); % creating dictionary of dictionary
x_1 = dictionary; % creating a dictionary to map to x
x_1({[1,2,3]}) = 5; % assigning a cell as key and 5 as value
x(1) = x_1; % mapping 1 as key and x_1 as value to x
Now when I want to map something to the dictionary of x(1) how to perform it?
Something like this:
x(1)({[1,3,4]}) = 6; % this errors
But I am not able do something like this because of indexing issues
So I tried:
x_1 = x(1);
x_1({[1,3,4]}) = 6;
x(1) = x_1;
But this seems like a lot of time wasted, by making a copy of x(1) to x_1, and then performing the operation and mapping it back. Is there any better way to do this?
Thanks in advance!

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chicken vector
chicken vector 2023년 5월 6일
편집: chicken vector 2023년 5월 6일
The impossibility of multiple indexing is a remarkable limitation that has also been discussed on the forum.
Unfortunately, I don't think there is an answer that might completely satisfy our needs of brevity.
A workaround for when you have only two layers of dictionaries is to use cells:
x = dictionary;
x_1 = dictionary;
x_1({[1,2,3]}) = 5;
x(1) = {x_1};
x{1}({[1,2,3]})
ans = 5
Otherwise you can use function handles for an indefinite number of subdictionaries:
getValue = @(dict,key) dict(key);
x = dictionary;
x_1 = dictionary;
x_1({[1,2,3]}) = 5;
x(1) = x_1;
getValue(getValue(x,1),{[1,2,3]})
ans = 5
  댓글 수: 2
Ajay Reddy
Ajay Reddy 2023년 5월 6일
Thanks a lot! It helped
chicken vector
chicken vector 2023년 5월 6일
Glad it did

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