why cannot generate the sequence of Years

>> s=datetime('2014','Format','y');

ss=datetime('2019','Format','y');

t1 =s:years(1):ss;

t2= s+ years(1:5);

%

disp(t1);

disp(t2);

2014 2015 2016 2016 2017

2015 2016 2016 2017 2019

[Dai Chao]

why t1 is not 2014 2015 2016 2017 2018 and 2019, and why t2 is not 2015 2016 2017 2018 and 2019?

Answer 1

[Steven Lord]

Let's look at your vectors in a different format, with day and month information not just year information.

 s=datetime('2014','Format','y');
 ss=datetime('2019','Format','y');
 t1 =s:years(1):ss; t1.Format = 'dd-MMM-yyyy'

t1 = 1×5 datetime array
   01-Jan-2014   01-Jan-2015   01-Jan-2016   31-Dec-2016   31-Dec-2017

 t2= s+ years(1:5); t2.Format = 'dd-MMM-yyyy'

t2 = 1×5 datetime array
   01-Jan-2015   01-Jan-2016   31-Dec-2016   31-Dec-2017   01-Jan-2019

You want to use calendar years (which account for leap years) rather than years (which don't) as stated in the Description section of the years function.

 t3 = s:calyears(1):ss; t3.Format = 'dd-MMM-yyyy'

t3 = 1×6 datetime array
   01-Jan-2014   01-Jan-2015   01-Jan-2016   01-Jan-2017   01-Jan-2018   01-Jan-2019

 t4 = s + calyears(1:5); t4.Format = 'dd-MMM-yyyy'

t4 = 1×5 datetime array
   01-Jan-2015   01-Jan-2016   01-Jan-2017   01-Jan-2018   01-Jan-2019

[Dai Chao]

Thanks for the answer.