How do I fix the error invalid use of operator?

T = 623;FAO = 29.9;CAO = 13114;VAO = 0.00228;Ko = 0.0000351;D = 0.5;
E = 72.38;x = 0.95;R = 8.314;dHr = 62.9;Dj = 0.6;Kh = 0.58;Dt = 0.5;
Kp = 0.145;Th1 =368;Th2 =296;Mp = 1.736;n = 5.2;nh = 0.932;nw = 0.281;
v = 0.0224; p = 790;Cp = 4.184;np = 20;ns =5.2;Tr =0.05;Kr =0.162;Ud = 0.764;
K = Ko*exp(-E/(R*T))
%Concentration of the feed
C = CAO*(1-x)@(x)1./(1-x);
%Parameters of the reactor
V = (FAO/(K*CAO))*quad(@(x)1./(1-x),0,0.95)
L = (4*V)/(pi*D^2)
St = V/VAO
Sv = 1./St
%Total heat load
Q = dHr*x*FAO
Hr = Q/V
Gp = Mp/(pi*(0.25^2))
NRE = (Gp*D)/n
% Friction factor
Jh = 0.027/(NRE^2)
%Pressure drop
P = (8*Jh*(L/D)*p*(v^2))/2
%Parameters of Reactor jacket
dT = Th1-Th2;Mh = Q/(Cp*dT)
%Mass Flow Rate of heating Fluid per Unit Volume of Reactor 
Mhr = Mh/V
%Film Heat Transfer Coefficient for Reactor Jacket
Gh = Mh/(pi*0.3^2)
Zn = Kh/Dj;Rn =(Dj*Gh)/nh;Pr =(Cp*nh)/Kh;Vn =nh/nw
hj = 0.023*(Kh/Dj)*(Rn^0.8)*(Pr^(1/3))*(Vn^0.14)
%Film Heat Transfer Coefficient for Reactor Tank Side
Znt = Kp/Dt;Rnt =(Dt*Gp)/np; Prt =(Cp*np)/Kp; Vnt =np/ns
ht = 0.054*(Kp/D)*(Rnt^0.66)*(Prt^(1/3))*(Vnt^0.14)
% Overall Heat transfer coeffient
y=(1./ht)+(Tr/Kr)+(1./hj);Uo =(1./y)
%Log Mean Temperature
dT1=T-Th2; dT2=T-Th1; dTm = dT2/dT1
Tm = (dT2-dT1)/(log10(dTm))
%Heat Transfer Area 
A = Q/(Uo*Tm)
%Clean Overall Film Transfer Coefficient
Uc = (hj*ht)/(hj+ht)
%Fouling Resistance
Rf =(Uc-Ud)/(Ud*Uc)
plot(V,T), xlabel('V (m^3)'), ylabel('T (k)'), title('Temperature against Volume Graph')

Answer 1

[KSSV]

You should change this line:

C = CAO*(1-x)@(x)1./(1-x);

to

C = @(x) CAO*(1-x).*1./(1-x);

[Ta Duc]

I dont know why it does not graph for me? Can you help me? Thanks a lot

[KSSV]

It is becuase you are using only a single value. You need to input array of values to get graph.

[Ta Duc]

Can you help me? Im not good at this.