How do I find out the number of neurons in layers?

조회 수: 8 (최근 30일)
Veronika
Veronika 2015년 3월 30일
답변: Greg Heath 2015년 4월 1일
Dear all,
I have this code for training neural network (RBF) :
load('trenovaci_modely1_velky')
disp('Trénovací modely byly načteny.')
P = [velky_tvar{1,:}];
T = [velky_tvar{2,:}];
net = newrb(P,T,0,0.3)
save net
disp('Neuronová síť byla uložena.')
I need to know how many neurons are in layers? Does anyone have any idea? Thank you for your answers.

채택된 답변

Greg Heath
Greg Heath 2015년 4월 1일
% newrb( x, t ,MSEgoal, spread, Nbmax, dNdisp )
% x - I x N matrix of N "I"nput vectors.
% t - O x N matrix of N "O"utput target vectors.
% MSEgoal - Mean squared error goal, default = 0.0.
% spread - Spread of radial basis functions, default = 1.0.
% Nbmax - Maximum number of basis neurons, default is N.
% dNdisp - Number of neurons to add between displays, default = 25.
'BUG: Output listing WILL SKIP line for neurons = 1 '
close all, clear all, clc
[ x, t ] = simplefit_dataset;
[ I N ] = size(x) % [ 1 94 ]
[ O N ] = size(t) % [ 1 94 ]
zx = zscore( x',1 )'; % Standardize to zero-mean/unit-variance
zt = zscore( t',1 )';
figure(1)
plot( zx, zt )
hold on
MSEgoal = 0.01*mean(var(zt',1)) % 0.01
spread = 1
Nbmax = N - 2*round(0.15*N) % 66 ~ 0.7*N
dNdisp = 1
[ net tr ] = newrb( zx, zt, MSEgoal, spread, Nbmax, dNdisp);
% NEWRB, neurons = 0, MSE = 1
' 'BUG: SKIPS neurons = 1 OUTPUT LISTING '
% NEWRB, neurons = 2, MSE = 0.272804
% NEWRB, neurons = 3, MSE = 0.267621
% NEWRB, neurons = 4, MSE = 0.181115
% NEWRB, neurons = 5, MSE = 0.0811973
% NEWRB, neurons = 6, MSE = 0.0246589
% NEWRB, neurons = 7, MSE = 0.0115911
% NEWRB, neurons = 8, MSE = 0.00415462
epochs = tr.epoch; MSE= tr.perf;
result = [ epochs' MSE' ]
% result = epoch MSE
% 0 1
% 1 0.29336
% 2 0.2728
% 3 0.26762
% 4 0.18112
% 5 0.081197
% 6 0.024659
% 7 0.011591
% 8 0.0041546
y = net(zx);
figure(1)
hold on
plot( zx, y, 'r.')
e = zt-y;
NMSE = mse(e) %0.004154
Nw = net.numWeightElements % 25
H = (Nw-O)/(I+1+O) % 8
H = size(net.IW{1},1)
H = size(net.b{1},1)
H = size(net.LW{2},2)
Hope this helps
Thank you for formally accepting my answer.
Greg

추가 답변 (1개)

Vinod Sudheesh
Vinod Sudheesh 2015년 4월 1일
You could do this by querying the "size" property of each of the individual neural network layers. For example, please see the code snippet below:
>> net=feedforwardnet([10 11 12]);
>> net.layers{1}.size
>> net.layers{2}.size
>> net.layers{3}.size
  댓글 수: 1
Greg Heath
Greg Heath 2015년 4월 1일
Not for NEWRB!
If [ I N] = size(input) [ O N ] = size(target)
the initial pretraining topology is I-O and the final postraining topology will be I-H-O.
However, H is unknown until the training is complete.

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