〖cos〗^2 (2π/4)sin(​5π/7)^2+ta​n(π/3 ln⁡35 )/√17

조회 수: 23 (최근 30일)
Mohammed Ali
Mohammed Ali 2023년 3월 28일
답변: Sai 2023년 4월 4일
how to write it in matlab
  댓글 수: 5
Torsten
Torsten 2023년 3월 28일
(cos((2*pi)/4))^2
ans = 3.7494e-33
(sin((5*pi)/7))^2
ans = 0.6113
(tan((pi/3)*(log(35))))
ans = 0.6574
sqrt(17)
ans = 4.1231
Now put the parts together.
Torsten
Torsten 2023년 3월 28일
You shouldn't use so many brackets:
cos(2*pi/4)^2 * sin(5*pi/7)^2 + tan(pi/3*log(35)) / sqrt(17)
ans = 0.1594
(cos((2*pi)/4)^2)*(sin((5*pi)/7)^2)+((tan((pi/3)*(log(35))))/sqrt(17))
ans = 0.1594

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답변 (1개)

Sai
Sai 2023년 4월 4일
Hi Mohammed,
I understand that you wanted to perform the above mathematical operation in MATLAB
You can follow the below approach to solve the mathematical operation:
a = (cos(2*pi/4))^2
b = (sin(5*pi/7))^2
c = tan((pi/3)*(log(35)))/sqrt(17)
Ans = (a*b)+c
Hope this helps you resolve the query.

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