# eig(a,b) matlab symbolic

조회 수: 3(최근 30일)
mohamdi mohamed 2023년 3월 17일
댓글: Sam Chak 2023년 4월 18일
hi, need some help
How do you find the eigenvalues of 2 symbolic matrix in Matlab?
i have this:
syms k1 k2 kx m1 m2 W
K = [ k1 + kx -kx 0
-kx k2 + kx -k2
0 -k2 k2]
M =[ 2*m1 0 0
0 2*m2 m2
0 m2 2*m2]
[V,D]=eig(K,M);
it retun me
Error using sym/eig
Too many input arguments.
but when i give value to k1 k2 m1 m2 its work
i need D with symbolic value some one can help me please

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### 채택된 답변

Sam Chak 2023년 3월 17일
Are you looking for the analytical solution like this?
syms k1 k2 kx m1 m2
K = [k1+kx -kx 0;
-kx k2+kx -k2;
0 -k2 k2]
K = M =[2*m1 0 0;
0 2*m2 m2;
0 m2 2*m2]
M = [V, Lambda] = eig(M*inv(K))
V = Lambda = ##### 댓글 수: 4표시 이전 댓글 수: 3숨기기 이전 댓글 수: 3
Sam Chak 2023년 4월 18일
Since you asked for a symbolical solution for eigenvalues, then that's the one produced by MATLAB eig() function that requires solving 3rd-degree polynomial equation. A 3rd-degree polynomial has analytical solutions. However, because there are many other parameters in the matrices, the given solution looks complicated.
I think the solution is already in the simplest form, as I don't find any terms that can be cancelled out or reducible. If you wish to solve it by hand, please look up Cardano's formula.

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### 추가 답변(1개)

mohamdi mohamed 2023년 3월 17일
i find this way
Dyn= M*inv(K)
[V,lambda]=eig(Dyn)

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