Why do I get "Array indices must be positive integers or logical values" error?

조회 수: 3 (최근 30일)
Arif Najmi
Arif Najmi 2023년 1월 30일
답변: Askic V 2023년 1월 30일
lc= 0.03
b=0.013
Rc= 0.0275
theta1= 0:15:360
theta2=theta1*pi/180
x=lc/2;
y=((Rc^2)*(theta2))
z=((b^2)*0.5)*(sin((theta1).*2))
r=b*(sin(theta1))
u1=Rc^2
u2=r.^2
u=r.*(((u1)-(u2)).^1/2)
rr=Rc^2*atan(r/u)
Vc=x(y+z-u-rr)
Why can't solve? Can someone help me?

답변 (2개)

Arif Hoq
Arif Hoq 2023년 1월 30일
try this:
lc= 0.03;
b=0.013;
Rc= 0.0275;
theta1= 0:15:360;
theta2=theta1*pi/180;
x=lc/2;
y=((Rc^2)*(theta2));
z=((b^2)*0.5)*(sin((theta1).*2));
r=b*(sin(theta1));
u1=Rc^2;
u2=r.^2;
u=r.*(((u1)-(u2)).^1/2);
rr=Rc^2*atan(r/u);
Vc=x*(y+z-u-rr)
Vc = 1×25
1.0e-04 * -0.1782 -0.1614 -0.1220 -0.0783 -0.0518 -0.0384 -0.0107 0.0362 0.0710 0.0868 0.1066 0.1463 0.1909 0.2132 0.2268 0.2592 0.3043 0.3381 0.3521 0.3732 0.4169 0.4576 0.4786 0.4937 0.5271

Askic V
Askic V 2023년 1월 30일
You asked why, and the answer is because of this line:
Vc=x(y+z-u-rr)
here, x is considered an array and y+z-u-rr is an index. basically you're trying to access an element of the array throught its index. Indices should be positive integers or logical values and not numbers with decimal points.
So this is probably a typo and Arif corrected this line to be:
Vc=x*(y+z-u-rr)

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