write the next column of one array to the previous column of another array

if (k~=i)>0) 
    for l=1:L1     
        I(:,k,b) = aa(k,:,l,b)' ;  
    end
end 

Here, for the case where k=i, 0 is entered in the kth column of the I matrix, but I don't want 0 to be entered and I want the next k+1 value of the aa matrix to be written in the kth column of the I matrix. So K=10 but I want to remove the case where k=i and make the size of the I matrix 9. How can I do this?

[Dyuman Joshi]

It is quite unclear what exactly you want to do.

"So K=10 but I want to remove the case where k=i and make the size of the I matrix 9."

For which matrix do you want to make the size 9? Which dimension of size? We don't know the size of arrays I and aa.

It will be better if you give a proper example with data of what you want to do.

Answer 1

[Sargondjani]

One problem in your current code is that you are overwriting I(:,k,b) for every l. so you might as well use:

for l=L1 

(instead of for l=1:L1 )

Anyway, i think you want something like

    i2 = 0
    for i=1:k
        if (k~=i)
            i2=i2+1
            I(:,i2,b) = aa(i,:,l,b)' ;  
        
        end
    end