Remove NaN Entries in a Dataset

조회 수: 18 (최근 30일)
Allen Hammack . 2023년 1월 20일
댓글: Allen Hammack . 2023년 1월 30일
I have a data set with multiple variables (var1, var2, var3). Any of the variables can have a NaN values. If one value for one of the variables is a NaN, I'd like to remove that instance for each variable. I have the following code that does this, but is very slow:
count = 1;
for j = 1:length(var1)
if isnan(var1(j)) == 1 || ...
isnan(var2(j)) == 1 || ...
isnan(var3(j)) == 1
else
var1_cull(count,1) = var1(j);
var2_cull(count,1) = var2(j);
var3_cull(count,1) = var3(j);
count = count + 1;
end
end
How can I modify this routine to have the speed up the data removal?
I've tried using the find() function, but I haven't been able to get it to work when checking to see if each variable is a nan.
Thank you!
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Allen Hammack 2023년 1월 30일
I have incorporated your suggestion and everything is working perfectly! Thank you!

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채택된 답변

Vilém Frynta 2023년 1월 20일
편집: Vilém Frynta 님. 2023년 1월 20일
You do not need to go through every element of vector with for loop.
You can use isnan on the vector, which will give you logical vector (0s and 1s), which you can then use on all the other vectors. You can also combine logical vectors together.
I will try my best to demonstrate:
% Random vars for demonstration
var1 = [1, 2, 3, NaN, 5, 6];
var2 = [9, NaN, 7, 6, 5, 4];
% 1 = NaN values, we will invert this later (~)
idx1 = isnan(var1);
idx2 = isnan(var2)
idx2 = 1×6 logical array
0 1 0 0 0 0
% Combine logical vectors
idx = idx1 | idx2
idx = 1×6 logical array
0 1 0 1 0 0
% Apply logical vector to your variables
var1(~idx)
ans = 1×4
1 3 5 6
var2(~idx)
ans = 1×4
9 7 5 4

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