I am trying to solve this problem using a MATLAB. I have attached the problem itself along with the code I have written so far. When I run the code I get an error that says 'Array indices must be positive integers or logical values.'
t = 0:5;
x = sqrt(2)*(1+1i)*exp(1i*(pi/4))*exp((-1+((1i)*2*pi)*t));
re = real(x);
imaginary = imag(x);
plot(re)
hold on
plot(imaginary)

 채택된 답변

Image Analyst
Image Analyst 2023년 1월 19일

0 개 추천

This works just fine:
t = linspace(0, 5, 500);
x = sqrt(2) * (1+1i) * exp(1i*(pi/4)) * exp((-1+((1i)*2*pi)*t));
re = real(x);
imaginary = imag(x);
plot(re, 'b-', 'LineWidth', 2)
hold on
plot(imaginary, 'r-', 'LineWidth', 2)
legend('Real Part', 'Imaginary Part', 'Location', 'northwest')
grid on;
xlabel('t');
ylabel('x real or imaginary part')
title('x = sqrt(2) * (1+1i) * exp(1i*(pi/4)) * exp((-1+((1i)*2*pi)*t))')

댓글 수: 8

collegestudent
collegestudent 2023년 1월 20일
The graph for Real should look like this, is there a way to plot it like this in MATLAB?
Torsten
Torsten 2023년 1월 20일
편집: Torsten 2023년 1월 20일
Change
t = linspace(0, 5, 500);
x = sqrt(2) * (1+1i) * exp(1i*(pi/4)) * exp((-1+((1i)*2*pi)*t));
to
t = linspace(-2, 2, 400);
x = sqrt(2) * (1+1i) * exp(1i*(pi/4)) * exp((-1+(1i)*2*pi)*t);
This is my updated code, however for x(t+2)+x(t+2) the plot is not produced and I get an error saying 'Array indices must be positive integers or logical values'
t = linspace(-2, 2, 400);
x = sqrt(2) * (1+1i) * exp(1i*(pi/4)) * exp((-1+(1i)*2*pi)*t);
re = real(x);
imaginary = imag(x);
eq = x.*(t+2)+x.*(t+2);
plot(re, 'b-', 'LineWidth', 2)
hold on
plot(imaginary, 'r-', 'LineWidth', 2)
hold on
plot(eq, 'LineWidth', 2)
legend('Real Part', 'Imaginary Part', 'x(t+2)+x*(t+2)', 'Location', 'northwest')
grid on;
xlabel('t');
ylabel('x real or imaginary part')
title('x = sqrt(2) * (1+1i) * exp(1i*(pi/4)) * exp((-1+((1i)*2*pi)*t))')
Torsten
Torsten 2023년 1월 20일
편집: Torsten 2023년 1월 20일
x(t+2)+x*(t+2)
does not mean
x*(t+2)+x*(t+2)
x is a function that depends on t.
You are asked to evaluate x and x* at t+2 and add the results.
collegestudent
collegestudent 2023년 1월 20일
But x and t are already defined so wouldnt it take the value of t and add 2 and then evaluates the x(t+2)
Torsten
Torsten 2023년 1월 20일
편집: Torsten 2023년 1월 20일
For this part of the assignment, you should define x as a function handle:
x= @(t) t.^2;
t = 4;
x(t+2)
ans = 36
x(6)
ans = 36
collegestudent
collegestudent 2023년 1월 20일
편집: collegestudent 2023년 1월 20일
But I already have x defined so I should rename it to be say xt when defining it as a function handle?
Update I added your suggestion to define x but it did not plot x(t+2)+x*(t+2)
x = @(t)sqrt(2) * (1+1i) * exp(1i*(pi/4)) * exp((-1+(1i)*2*pi)*t);
t = linspace(-2, 2, 400);
hold on
plot(t,real(x(t)))
plot(t,imag(x(t)))
plot(t,x(t+2)+conj(x(t+2)))
hold off
grid on

댓글을 달려면 로그인하십시오.

추가 답변 (2개)

John D'Errico
John D'Errico 2023년 1월 19일
편집: John D'Errico 2023년 1월 19일

0 개 추천

Do not define a variable with the names: sqrt, exp, real, imag, plot
If you do, then what do you think will happen when you then try to use the functions of the same name? Should MATLAB know what you want it to do? Sorry, but computers are very literal things. They try to do what you tell them to do. But when you tell them to do something confusing, what do you expect?
Do this at the command line:
which sqrt -all
which exp -all
which real -all
which imag -all
which plot -all
One of those will tell you that you have created a variable by that name. Delete the offending variable. My guess would be the problem lies in one of the names exp, real, or imag.
You could also have just looked at the list of variable names. So my guess is this would tell you something useful:
whos exp real imag
As if any of those variable names were used by you, they would now show up.

댓글 수: 3

I added the lines below at the beginning of my code and now the error has gone away, however the plot does not look like what I am trying to get
clear variables;
close all;
Torsten
Torsten 2023년 1월 19일
Do you know what exp(2*pi*1i*t) is for t=0:5 ? So the plot result shouldn't surprise you.
collegestudent
collegestudent 2023년 1월 19일
the time vector of t = 0:5; is not given in the equation. I just set it to be that for testing purposes, howeer the plot should be a sin wave with envolopes

댓글을 달려면 로그인하십시오.

Sydney Lang
Sydney Lang 2023년 1월 19일

0 개 추천

You haven't defined t. If you do, the code works.
Additionally you haven't mentioned where this error occurs. I assume its coming from how you defined t?

댓글 수: 1

I adjusted my code but the error still occurs along with an error at line 5
t = 0:5;

댓글을 달려면 로그인하십시오.

카테고리

도움말 센터File Exchange에서 Discrete Data Plots에 대해 자세히 알아보기

제품

릴리스

R2022b

질문:

2023년 1월 19일

편집:

2023년 1월 20일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by