using linspace in a matrix incrementing by a certain number
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in a row of a matrix I need start with 51 and subtract 7.25 each time, 4 times, so the row would look like
51 43.75 36.5 29.25 22
I have
A=[2 4; 6 8]
B=[A(1,2:-1:1) A(1,2:-1:1) ; A(2,2:-1:1) A(2,2:-1:1);linspace(51,22,4)]
but the result is
A =
2 4
6 8
B =
4.0000 2.0000 4.0000 2.0000
8.0000 6.0000 8.0000 6.0000
51.0000 41.3333 31.6667 22.0000
and is incorrect
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답변 (2개)
Walter Roberson
2023년 1월 19일
that would be a row of 5 values inside a matrix that has 4 columns not 5. That is not possible
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Steven Lord
2023년 1월 19일
There are several functions for creating regularly spaced vectors of given lengths depending on which three of the four parameters (start point, end point, increment, and number of points) you know.
- For start point, end point, increment use colon.
startPoint = 1;
endPoint = 10;
increment = 0.5;
numPoints = 19;
x1 = startPoint:increment:endPoint
- For start point, end point, number of points use linspace.
x2 = linspace(startPoint, endPoint, numPoints)
- For start point, increment, number of points use colon.
x3 = startPoint + increment*(0:numPoints-1)
- For end point, increment, number of points use colon. This one essentially flips the sign of the increment and the vector from the start point, increment, number of points case. Or you could negate the sign of the increment, use the (start point, increment, number of points) case, then flip the resulting vector.
x4 = endPoint + increment*((1-numPoints):0)
startPoint2 = endPoint;
x5 = flip(startPoint2 + (-increment)*(0:numPoints-1))
Are they all the same?
[isequal(x1, x2), isequal(x2, x3), isequal(x3, x4), isequal(x4, x5)]
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