Lsim function returns an array filled with Nan

Im using lsim to simulate a MVE, for some reason the response y2 is filled with NaN when It should have the system response.
R=1;
C1=1*10^-6;
L=1*10^-3;
A= [1/C1 -1/C1 0; -2*(R/L) R/L -1/L; R/L (-5/2)*(1/L) 1/L];
B= [0 0; 1/L 0; 0 -1/(2*L)];
C= [0 1/2 0; 0 0 1];
D= [0 1/(2*R); 0 0];
sys = ss(A,B,C,D);
t2 = 0:0.01:20;
u1 = 5*heaviside(t2-3);
u2 = 10*heaviside(t2-6);
u = [u1(:), u2(:)];
[y2,t2]=lsim(sys,u,t2);
y2
y2 = 2001×2
NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN

답변 (1개)

Paul
Paul 2023년 1월 12일
Hi Gabriel,
Recheck the model. As written it has two unstable poles way out in the right half plane. That will be very difficult to simulate.
R=1;
C1=1*10^-6;
L=1*10^-3;
A= [1/C1 -1/C1 0; -2*(R/L) R/L -1/L; R/L (-5/2)*(1/L) 1/L];
B= [0 0; 1/L 0; 0 -1/(2*L)];
C= [0 1/2 0; 0 0 1];
D= [0 1/(2*R); 0 0];
sys = ss(A,B,C,D);
format short e
eig(sys)
ans = 3×1
1.0e+00 * 1.0020e+06 1.5801e+03 -1.5791e+03
Also, be careful using heaviside. If using the default sympref, then we have
heaviside(0)
ans =
5.0000e-01
You can change that 1 using sympref, which is probably what you want. Or define a new function like
unitstep = @(t) 0.5*(t==0) + heaviside(t);
unitstep(0)
ans =
1

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질문:

2023년 1월 12일

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2023년 1월 12일

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