Different tick values on same axis

I want to use xticks using different steps. From a to a+g the step dxs, from a+g to b-g the step dxf and from b-g to b again the step dxs. Can it be used in the same command? Thank you in advance.

a=0;
b=4;
c=0;
d=6;
g=1;
dxs=0.2;
dxf=0.25;
dy=0.5;
figure(1)
plot([a b b a a],[c c d d c])
hold on
axis([a-1 b+1 c-1 d+1])
hold on
plot([a+g b-g b-g a+g a+g],[c c d d c])
hold on
axis([a+g-1 b-g+1 c-1 d+1])
grid on
axis tight
axis equal
xticks([a:dxs:a+g])
yticks([c:dy:d])

Answer 1

[Star Strider]

See if the xticks call in:

xticks([a+g:dxf:b-g (b-g+dxs):dxs:b])

does what you want —

a=0;
b=4;
c=0;
d=6;
g=1;
dxs=0.2;
dxf=0.25;
dy=0.5;
figure(1)
plot([a b b a a],[c c d d c])
hold on
axis([a-1 b+1 c-1 d+1])
hold on
plot([a+g b-g b-g a+g a+g],[c c d d c])
hold on
axis([a+g-1 b-g+1 c-1 d+1])
grid on
axis tight
axis equal
xticks([a:dxs:a+g (a+g)+dxf:dxf:b-g (b-g)+dxs:dxs:b])                   % NEW
Check = xticks                                          % Check Values (Optional)

Check = 1×19

0 0.2000 0.4000 0.6000 0.8000 1.0000 1.2500 1.5000 1.7500 2.0000 2.2500 2.5000 2.7500 3.0000 3.2000 3.4000 3.6000 3.8000 4.0000

% xticks([a:dxs:a+g])
yticks([c:dy:d])

The xticks argument values have to increase, so two adjacent values of (b-g) are not permitted.

.

[Alexandra Roxana]

Thank you!

[Star Strider]

As always, my pleasure!

[Star Strider]

I initially missed the [a:dxs:(a+g)] part. Early here. Fixed now.

[Alexandra Roxana]

I've already put it, no worries!

[Star Strider]

Thank you!

Answer 2

[Bora Eryilmaz]

You can generate a ticks vector, which should be sorted and with unique elements:

a=0;
b=4;
c=0;
d=6;
g=1;

dxs=0.2;
dxf=0.25;
dy=0.5;

figure(1)
plot([a b b a a],[c c d d c])
hold on
plot([a+g b-g b-g a+g a+g],[c c d d c])

grid on
axis tight
axis equal

% Set axis limits
ax = gca;
ax.XLim = [a b];
ax.YLim = [c d];

% Ticks vectors
x_ticks = unique([a:dxs:(a+g), (a+g):dxf:(b-g), (b-g):dxs:b], 'stable');
xticks(x_ticks)
yticks([c:dy:d])

[Alexandra Roxana]

Thank you for your answer!