How to describe right hand side of energy equation in tridiagonal system? Didn't get right hand side values of tridiagonal matrix.
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xmax=1; ymax=20; dx=0.05; dy=0.25; dt=0.02; m=xmax/dx; n=ymax/dy; U=zeros(m,n); V=zeros(m,n);
for j =1:n
D(i)=-U(i,j)*dt*(-TNEW(i-1,j)+TOLD(i,j)-TNEW(i-1,j))/2*dx+dt*(TOLD(i,j-1)-2*TOLD(i,j)+TNEW(i,j+1)/2*(dy^2))-V(i,j)*dt*(TNEW(i,j+1)-TOLD(i,j-1))/4*dy;
end
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답변 (1개)
Prateek
2023년 1월 6일
Hello Gayathri,
The code you have posted executes without any error.
For better assistance, please post more details about your query, and include any other code and/or error messages .
Regards,
Prateek
댓글 수: 1
Prateek
2023년 1월 9일
Hello Gayathri,
Please refer to these links:
Thanks,
Prateek
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