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How to describe right hand side of energy equation in tridiagonal system? Didn't get right hand side values of tridiagonal matrix.

조회 수: 1 (최근 30일)
xmax=1; ymax=20; dx=0.05; dy=0.25; dt=0.02; m=xmax/dx; n=ymax/dy; U=zeros(m,n); V=zeros(m,n);
for j =1:n
D(i)=-U(i,j)*dt*(-TNEW(i-1,j)+TOLD(i,j)-TNEW(i-1,j))/2*dx+dt*(TOLD(i,j-1)-2*TOLD(i,j)+TNEW(i,j+1)/2*(dy^2))-V(i,j)*dt*(TNEW(i,j+1)-TOLD(i,j-1))/4*dy;
end

답변 (1개)

Prateek
Prateek 2023년 1월 6일
Hello Gayathri,
The code you have posted executes without any error.
For better assistance, please post more details about your query, and include any other code and/or error messages .
Regards,
Prateek

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