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Image Analyst
Image Analyst 2023년 1월 1일
I can't read that language but the equation goes in MATLAB exactly as it is written there. That is proper syntax.
daniel
daniel 2023년 1월 1일
Write a function velocity(x,y,z,t) that calculates the instantaneous speed when parameters are given and the following formula is known:
v= sqrt(diff(x).^2+diff(y).^2+diff(z).^2)./diff(t);
Note: The calculation of the function can only be performed when the size of the vectors t,z,y,x have the same size (length).
Torsten
Torsten 2023년 1월 1일
function v = velocity(x,y,z,t)
v = sqrt(diff(x).^2+diff(y).^2+diff(z).^2)./diff(t);
end
Done.
daniel
daniel 2023년 1월 1일
The calculation of the function can only be performed when the size of the vectors t,z,y,x have the same size (length).
Torsten
Torsten 2023년 1월 1일
편집: Torsten 2023년 1월 1일
Yes, then supply t,x,y and z as vectors of the same length.
Or check their lengths in the function.
daniel
daniel 2023년 1월 1일
Walter Roberson
Walter Roberson 2023년 1월 1일
In the case of that error message, the problem is that you had accidentally created a variable named velocity that you are then trying to index. If there is a variable in scope and a function of the same name, MATLAB gives priority to the variable in scope.

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Image Analyst
Image Analyst 2023년 1월 1일

0 개 추천

Try this:
v = velocity([0, 5.6, 7], [0, 1.1, 2.4], [0, 4, 20], [0, 1, 2])
v = 1×2
6.9692 16.1137
function v = velocity(x,y,z,t)
v = [];
if ~isequal(size(x), size(y)) || ~isequal(size(x), size(z)) || ~isequal(size(x), size(t))
uiwait(errordlg('Sizes do not match'));
return;
end
v = sqrt(diff(x).^2+diff(y).^2+diff(z).^2)./diff(t);
end

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daniel
daniel 2023년 1월 1일
You must be running different code. I ran mine right here in answers. Paste your code in here, just like I did, then click the green run triangle.
What does this show if you type it in the command window?
which -all velocity
All you have is the m-file function, right? You don't have a variable called velocity, right?
daniel
daniel 2023년 1월 1일
daniel
daniel 2023년 1월 1일
its working tnks
Voss
Voss 2023년 1월 3일
@daniel: isequal accepts more than two input arguments and returns true if and only if all the inputs are equivalent.
That is, you can replace this:
if ~isequal(size(x), size(y)) || ~isequal(size(x), size(z)) || ~isequal(size(x), size(t))
with this:
if ~isequal(size(x), size(y), size(z), size(t))

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