Can you please tell me what is the error ?

조회 수: 3 (최근 30일)
Ahmed
Ahmed 2022년 12월 27일
답변: Karim 2022년 12월 27일
clc
clear all
E=70*10^6;
v=0.3;
p=50*10^3;
h=0.01;
a=0.5;
b=0.5;
syms x y
B=-h*[6*x*(b-2*y)/(a^(3)*b) 0 (a-6*x)*(b-2*y)/(2*a^2*b) -6*x(b-2*y)/(a^3*b) 0 -(a+6*x)*(b-2*y)/(2*a^2*b) -6*x*(b+2*y)/(a^3*b) 0 -(a+6*x)*(b+2*y)/(2*a^2*b) 6*x*(b+2*y)/(a^3*b) 0 (a-6*x)*(b+2*y)/(2*a^2*b);6*(a-2*x)*y/(a*b^3) -(a-2*x)*(b-6*y)/(2*a*b^2) 0 6*(a+2*x)*y/(a*b^3) -(a+2*x)*(b-2*y)/(2*a*b^2) 0 -6*(a+2*x)*y/(a*b^3) (a+2*x)*(b+6*y)/(2*a*b^2) 0 -6*(a-2*x)*y/(a*b^3) (a-2*x)*(b+6*y)/(2*a*b^2) 0;4*(-3*b^2*x^2+a^2*(b^2-3*y^2))/(a^3*b^3) (b-2*y)*(b+6*y)/(2*a*b^2) -(a-2*x)*(a+6*x)/(2*a^2*b) (12*b^2*x^2-4*a^2*(b^2-3*y^2))/(a^3*b^3) -(b-2*y)*(b+6*y)/(2*a*b^2) -(a-6*x)*(a+2*x)/(2*a^2*b) 4*(-3*b^2*x^2+a^2*(b^2-3*y^2))/(a^3*b^3) -(b-6*y)*(b+2*y)/(2*a*b^2) (a-6*x)*(a+2*x)/(2*a^2*b) (12*b^2*x^2-4*a^2*(b^2-3*y^2))/(a^3*b^3) (b-6*y)*(b+2*y)/(2*a*b^2) (a-2*x)*(a+6*x)/(2*a^2*b)];

채택된 답변

Karim
Karim 2022년 12월 27일
you forgot a * in -6*x(b-2*y)/(a^3*b) this should be -6*x*(b-2*y)/(a^3*b)
see below
E=70*10^6;
v=0.3;
p=50*10^3;
h=0.01;
a=0.5;
b=0.5;
syms x y
B=-h*[6*x*(b-2*y)/(a^(3)*b) 0 (a-6*x)*(b-2*y)/(2*a^2*b) -6*x*(b-2*y)/(a^3*b) 0 -(a+6*x)*(b-2*y)/(2*a^2*b) -6*x*(b+2*y)/(a^3*b) 0 -(a+6*x)*(b+2*y)/(2*a^2*b) 6*x*(b+2*y)/(a^3*b) 0 (a-6*x)*(b+2*y)/(2*a^2*b);
6*(a-2*x)*y/(a*b^3) -(a-2*x)*(b-6*y)/(2*a*b^2) 0 6*(a+2*x)*y/(a*b^3) -(a+2*x)*(b-2*y)/(2*a*b^2) 0 -6*(a+2*x)*y/(a*b^3) (a+2*x)*(b+6*y)/(2*a*b^2) 0 -6*(a-2*x)*y/(a*b^3) (a-2*x)*(b+6*y)/(2*a*b^2) 0;
4*(-3*b^2*x^2+a^2*(b^2-3*y^2))/(a^3*b^3) (b-2*y)*(b+6*y)/(2*a*b^2) -(a-2*x)*(a+6*x)/(2*a^2*b) (12*b^2*x^2-4*a^2*(b^2-3*y^2))/(a^3*b^3) -(b-2*y)*(b+6*y)/(2*a*b^2) -(a-6*x)*(a+2*x)/(2*a^2*b) 4*(-3*b^2*x^2+a^2*(b^2-3*y^2))/(a^3*b^3) -(b-6*y)*(b+2*y)/(2*a*b^2) (a-6*x)*(a+2*x)/(2*a^2*b) (12*b^2*x^2-4*a^2*(b^2-3*y^2))/(a^3*b^3) (b-6*y)*(b+2*y)/(2*a*b^2) (a-2*x)*(a+6*x)/(2*a^2*b)]
B = 

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Symbolic Math Toolbox에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by