What does the following code do?
이전 댓글 표시
clear all
close all
clc
x= input('Enter initial condition: ')
eps= input('Enter accuracy : ')
Nmax= 1e5
for N=1:Nmax
f= 2*x+exp(x/pi)+sin(pi*x)-20
df= 2+(1/pi)*exp(x/pi)+pi*cos(pi*x)
newx= x-f/df
if abs(newx-x)<=eps
disp(['The solotion is: ',num2str(newx)])
disp(['The number of attempts is: ',num2str(N)])
break
end
x=newx
end
if N==Nmax
disp('There is no solution for the given conditions!')
end
댓글 수: 3
John D'Errico
2022년 12월 26일
Talk to the source of the code Asing what uncommented junk code does is difficult to say, especially if we are given no clue as to what it is supposed to do. And, sorry, but this is junk code.
the cyclist
2022년 12월 26일
What your code will do is give the error message you see in red above (after I formatted your code, and ran it here).
daniel
2022년 12월 26일
답변 (1개)
Voss
2022년 12월 26일
0 개 추천
카테고리
도움말 센터 및 File Exchange에서 App Building에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!